All Answers 358194 Answers

Since the values in the table represent the points in a straight line, let's find the slope:

m  =  [ (-17) - (-14) ] / (p + 2) - (p) ]  =  -3 / 2   --->   m  =  -3/2

Now, let's find the equation of the line by using the point-slope formula:

y - (-5)  /  (-3/2)·(x - 2)   --->   y + 5  =  (-3/2)x + 3   --->   y  =  (-3/2)x - 2

For the point  (13, q):  y  =  (-3/2)x - 2   --->   q  =  (-3/2)(13) - 2   --->  q  =  -21.5

For the point  (p, 14):  y  =  (-3/2)x - 2   --->   14  =  (-3/2)(p) - 2   --->   p  =  -32/3

Left for you to finish ...  

This is a geometric sequence with a first term =717897987691852588770249/140737488355328 
Common Ratio = 2/3
Number of terms =99
Sum = [717897987691852588770249/140737488355328] * (1 - (2/3)^99) / (1 - 2/3), solve for S
S =1 5302916005.13719
The geometric mean =S^(1/99) =1.2672914563....

Please stop.

Solve system x = 1/4*y + a, y = 1/4*x + b

Add equations: x + y = 1/4*(x + y) + a + b

==> 3x + 3y = a + b

==> 3x + 3(1/4*x + b) = a + b

==> 3x + 3/4*x + 3b = a + b

==> 15/4*x = a - 2b

==> 15/4*y = b - 2a

==> -a - b = 15/4*x + 15/4*y

==> a + b = -15/4*x - 15/4*y

Plug in x = 1, y = 2 ==> a + b = -15/4 - 15/4*2 = -45/4

Um CPhill am I roght or wrong since we have different answers

so we have (10+500)*(500-10/2+1)/4=510*496/4=63240

So we get that the speed of Allen is 100/12=50/6=25/3 and the speed for Bruce is 100/15=20/3 so we have 100-20/3*12=100-80=20 so Bruce was 20 meters from the finish line

x^28*y^21 since it is a negative and we divide by a negative to get a bigger number so it is x^28/y^-21

1889568:1296=1458 so we get (1458)º

so it becomes 100*97+3*97=9700+97+97+97=9700+291=9911

so it becomes 2/3,6/5,12/7,20/9, so we have that the numerator is [number in sequence]^2+[number in sequence] and the denominator is 2*[number in sequence]+1 so we have that the 12th number in the sequence is ((12*12)+12)/(2*12+1)=(144+12)/25=156/25=6 6/25 so the 12th term is 156/25 or 6 6/25

so 50 out of 100 is 50/100=1/2=50% so since the other one is 62% we multiply them by 100 to get 62 and 62-50=12 so it is 12/(100/2)=12/50=6/25=24% so our final answer is 24%

productfor(n,1, 89, tan(n)) = 1

so the first sequence is (18-8)*48+18=498 and the last number is -232 so the formula is (498+-232)*99/2=13167 so the sum of the 99 terms is 13167

We round the thousandths place and that number will become the number that you want with 2 deciamls for example 1/7=0.14258...≈0.142≈0.14

The probability is 13/52*12/51*11/50 = 11/850.

You must consider the probability that drawing BB, BWB, WWB, or WWBB.  This gives you a probability of 2/9 + 5/81 + 12/81 + 6/81 = 41/81.

We have two options to consider: If the 0 that is removed is the middle digit or if 0 is the last digit.

Case 1: N=a0b

10a+b=(100a+b)/9

90a+9b=100a+b

8b=10a

4b=5a

b=5, a=4

Case 2: N=ab0

10a+b=(100a+10b)/9

90a+9b=100a+10b

10a=-b

The only answer for this is when a and b equal 0. But this number isn't a valid three digit number. 

So our answer is 405

We find the prime factorization of 21600:

2^5 x 3^3 x 5^2.

The number of multiples must be (5+1)(3+1)(2+1)=6*4*3=72 divisors.

Multiply the product 103*97 in your head.

Hello Guest!

\((a+b)(a-b)=a^2-b^2\)

\((100+3)\times (100-3)=10000-9=9991\)

This can easily be calculated in the head.

  !

103*97=103(100-3)=10300-309=9991.

Every even power of 9 ends in 1, every odd power ends in 9.  There are 51 even powers (including 9⁰) and 50 odd powers.

Summing these we get 51*1 + 50*9 = 501, so the sum ends in 1.

In 2004 the percentage was 50%. In 2005 the percentage was 62%. 62-50/50=12/50=24%.

solve for X (A, B, & C are constants): arctan(C/X)=arcsin((A-X)/B)

Is this what you are looking for?

x = prob of 1

x + 2x + 3x + 4x + 5x + 6x = 1

21x = 1

x = 1/21