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Well think about it this way. There are 18 groups of 5.
5+5+5+5+5+5+5+5+5+5+5+5+5+5+5+5+5+5

Lol 

I was about to say the same thing but we should not judge others...I would'nt want to hurt someones feelings. 

Oh nvm then...

xD I was a little confused.

Thx!

Lol, yes I'm pretty sure that's correct... See! You didn't even need much help, very smart  Good job!

Guest #2 Post is NOT the same person who posted the question. What made you think it was the same person?

∠PQC = 15 degrees

Let x be the number of crows and 15-x the number of groundhogs. Note that crows have 2 legs and groundhogs 4. We form an equation for the number of legs.

2x+4(15-x)=40

2x+60-4x=40

-2x=-20

x=10

There are 10 crows and 15-10=5 groundhogs.

Write 3x+4y=-14 in slope intercept form:

3x+4y=-14

4y=-3x-14

y=-3/4x-14/4

The line perpendicular to it must have slope of 4/3. So we have y=4/3x+b. We plug in the given point (-5, 7) to solve for b.

7=4/3(-5)+b

7=-20/3+b

b=41/3

m+b is 4/3+41/3=45/3=15.

I have a question:

I have tried solving this question and got 16. I just tried solving it and I think it's 16 because 2^4. One is tails, and the other is heads. So, 2. Since it is 4 times, I think 2^4. Is this correct?

Whoops. You just solved it.

1735 mod 5 =0. 1736 mod 7 =0. 1737 mod 9 =0. 1738 mod 11 =0. They are ALL in (D).

The common ration r = -4/9.  The infinite sum is given by a/(1-r), where a is the first term.

Can you take it from here?

\(3^x=243^4\\ 3^x=(3^5)^4\\\ 3^x=3^{20}\\ \boxed{x=20}\)

You can try to factor 243 out.

Create equivalent expressions in the equation that all have equal bases, then solve for x.

x=20

Work: 3^5=243

3x=243^4

(3^5)^4=243^4

3^20, which leads to x=20.

Hope this helps, whymenotsmart^m^