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-150x>=-2400

150x<=2400

x<=16

-336>=-21y

336<=21y

16<=y

y>=16

x is less than y.

The top angle in he triangle is 180^o - 121^o  =  59^o.

The angle in the right corner of the triangle is 180^o - 144^o  =  36^o.

This means that the angle in the left corner of the triangle is 180^o - (59^o + 36^o)  =  85^o                 

To find the value of n^o:  n^o  =  180^o - 85^o  =  95^o.

What was the purpose of writing [2 x 120] / 26 =240 / 26 at the bottom? Can you read at all??

My textbook doesn't accept rounded answers

The area of triangle PQR is 1/2*PQ*QR*sin(angle PQR) = 1/2*12*12*1/2 = 36.

should be A. because 36 plus 144 is 180, and that is the degree of the straight line that both the degrees are on. Hope this helps, whymenotsmart^m^.

Right scalene triangle.

Sides: a = 10   b = 24   c = 26

Area: T = 120
Perimeter: p = 60
Semiperimeter: s = 30

Angle ∠ A = α = 22.62° = 22°37'11″ = 0.395 rad
Angle ∠ B = β = 67.38° = 67°22'49″ = 1.176 rad
Angle ∠ C = γ = 90° = 1.571 rad

Height: ha = 24
Height: hb = 10
Height: hc = 9.231 ==[2 x 120] / 26 ==9.231 - The shortest altitude.

We can start by creating a horizontal line, making two figures, a triangle and a rectangle.

The area of the triangle = (12 * 5)/2 = 60/2 = 30 cm²

The area of the rectangle = 14 * 5 = 70 cm²

30+70 = 100 cm²

Please check you work, this is not correct

The years: 2000, 2400, 2900, 3300, 3800 would be "Leap Years" under the proposed scheme.

 We need to plug in the values that are given. So,

4w²  - v + 3u 

= 4(-4)²  -  5 + 3(2)

= 4(16) - 5 + 6

= 64 + 1

= 65

Volume of sphere = 4 /3 π r³

(a) Work out an estimate for the volume of the squash ball.

 Put in   r = 3.38 cm   into the above equation....answer will be in   units of   cm³

(3x    +     8 )(x   +    2 )     You can finish ,,,, 

(y+b)²  - (a + 3d)²

I THINK that is THREE separate questions.....please post them separately  so they are readable .....

Put y = 0 (this will be when the ball hits the ground) into the equation and then solve for 't'

0 = -16t² -60t +54     Solve for 't' 

                                   (throw out any negative values found while using Quadratic Fromula or factoring)

Thank you for the link!! I solved it the same way as Melody, but I am also struggling to find a way to prove it, so if possible I would like some help with that. 

Perhaps this link might help: 

https://web2.0calc.com/questions/i-am-thinking-of-a-positive-number-less-than-500-that-is-divisible-by-every-number-from-1-to-10-inclusive-with-one-exception-what-numb

 I t would be    ( 2 \(\sqrt[3]{2}\))⁶     = 64 * 2^6/3 = 64 * 2² = 256

TWO triangular ends      TWO x 1/2 b h =   TWO x 1/2 6 * 4  ft²

ONE rectangular bottom   6 * 9

TWO rectangular sides      TWO * 9 * 5

Add the REDs

Dividimos 21 por 2.5 para obtener 8.4.

21/2.5 =   8.4