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haha it's fine.

That is correct!

Thank you very much :D

Angle bisector means it halves the angle. So that means \(ABE=EBC\)\(\Rightarrow2x+20=4x-6\Rightarrow2x=26\Rightarrow x=13\). Plug that into \(2x+20\) to find ABE. \(2\times13+20\Rightarrow46\) and the answer is \(\boxed{46}\)

Heron's formula is \(\sqrt{s(s-a)(s-b)(s-c)}=area\) where s is the semi-perimeter (in less fancy words \(\frac{area}{2}\)) and a, b, c are the sides of the triangle. I'm pretty sure the guest did something wrong in the calculations there and that is why he/she was wrong

I also made another problem; I wanted it to be like the AMC8 contest:

Right after the Tiger Algebra Exam, Alex, Bob, and Caroline start discussing their answers.

Alex: I just realized that our answers are all 2 digit primes!

Bob: Woah! Really? Also, the sum of your two answers is the date of my birthday earlier this month! What about you Caroline?

Caroline: That's a coincidence. The sum of your two answers is the date of my birthday later this month! Woah. This exam is so weird!

Alex: The sum of your two answers is today's date. Cool!

What could be the exam date?

a) Jan. 24

b) Feb. 26

c) Mar. 28

d) Oct. 27

e) Nov. 13

Now, which is it?

- tigernathan

Hello... hope i didn't break into your conversation @gwenspooner85 

The formula for the sum in a infinite geometric sequence is \(\frac{{a}_{1}}{1-r}\) where a is the first term and r is the common ratio. We know that the sum equals 25 so \(\frac{{a}_{1}}{1-r}=25\). We also know the common ratio so \(\frac{{a}_{1}}{1+\frac{1}{3}}\Rightarrow\frac{{a}_{1}}{\frac{4}{3}}=25\). Solve for a and you get \(25\times\frac{4}{3}\Rightarrow\frac{100}{3}\) but it's asking for the second term (this is the first term) so we multiply \(\frac{100}{3}\) by \(-\frac{1}{3}\) (the common ratio) and you get \(-\boxed{\frac{100}{9}}\)

is the area of the square 1/2 * the area of the right triangle?
if it is then it would be \(\sqrt{3}\)

Hi, how's your day been :)

If Ali won 5 games, that means Veli and Selami lost 5 games combined. We know Veli lost 4 games so Selami lost 1 game. If Ali lost 3 games then Veli and Ali won 3 games in total. Veli won 1 game so Selami won 2 games.

I created a graph (hopefully gives you a headstart) and maybe try trial-and-error

I know that the length of BC is \(\frac{2\sqrt{10}}{3}\) : in decimal form is 2.10818510… but it is hard to find the cordinate

Thank you very much! However, I don't think that is a prime number :(

the greatest prime factor of 5^12 is 5 because the other ones last digit is 5 and since the last digit is 5 then it is a multiple of 5 but 5 is a prime that ends up with 5 so the greatest prime divisor of 5^12 is 5 . 5 * (10^6) = 2000000 and 2000000 + 2^12 = 2004096 so the answer is 2004096.

\((\frac{10-\sqrt{2}}{2})^2\) is the area of the shaded reigon

The number is 5^12 minus 2 times 10^6 plus 2^12, Guest.

Nice try, though :D

The greatest prime divisor of 5^12 is 5 .

5 - 2 = 3 x 1,000,000 =3,000,000.

2 x  2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 =4,096

3,000,000 + 4,096 =3,004,096

60 , 71 , 82 , 93 , Total =  4

Think about the pythag. triples

Write an equation where w is the width:

\(3w+6=100\)\(\Rightarrow3w=94\)

Try solving