I'll give you a few hints:
1) Draw an altitude h from D to a point F on line segment AM. h = 2r
2) Find the lengths of lines AF and FM
3) Use the Pythagorean theorem to find the length of DM.
(btw., ignore those suggested answers; the length of DM is totally different from those numbers.)
jimkey17's correct
We can pretend that 99=100-1 and plug it in to get (100-1)*3456 then we use the associative property of multiplication to get 100*3456-356=345600-3456 and we get 342144
You can actually do it in removing 20 numbers: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95 and the last and 20th number is 10. I think!
Oopsy. I think that was a typo. Thanks Melody :)
Okay, thanks!
If you divided 100! [which is 1 x 2 x 3 x 4 x 5..........x 98 x 99 x 100] by 5, 23 times and the 24th time divide it by 10, you will end up with 2 at the end of the still very large number. In fact, this is the number that you will end up with after dividing 100! by 5 some 23 times and divide it by 10 on the 24th time:
7 8287703748 2793470738 9236886635 8969387002 3897110337 7849044106 8567513352 1044008415 9164912362 4209837854 8214060408 2346158362 5595826977 8892685312 - which is 141 digits long after bringing it down from 158 digits (which is 100!).
Thank you so much! Does anyone know how to do the rest?
Ages NOW are x and x-2
TEN years ago their ages were x- 10 and x-2 -10 and totaled 48
x-10 + x-2-10 = 48
2x -22 = 48
2x = 70
x = 35 and the other is 35-2 = 33 y/o
x+x-2=48
2x=46
x=23
23+10=33
33-2=31
Pat is 31 and his wife is 33
Hmm you could be right.
In that case the probability would be
2 1 2 1
–– x –– = ––– or –––
11 10 110 55
a 2 out of 11 chance of getting the 10 or the 11 times
a 1 out of 10 chance of getting the other one.
.
Oh I thought you were replying to me.
Total are of flag = (2 + 1 + 1) * 2 = 8 units2
white area = 1*2 + 1*2 + 1/3 (2*2) = 4 + 4/3
5 1/3 / 8 = 16/ 24 = 2/3 is white
All of them have a single digit GCD except the following: 10, 20, 25, 30, 40, 50, 60, 70, 75, 80, 90 >Total =11 such numbers
3 + 4 + 5 = 12 could work. It's probably not the smallest.
the answer is 7
Hint: Find the slope using the 2 points, then take any of the two points and plug them into the equation y=mx+b then solve for b. use m and b to create the equation
REMINDER- y=mx+b, b=y intercept, m=slope, y=any y coordinate of a point thats on the line, x=any x coordinate of a point thats on the line
Let x be the number of games he played/winned today. We form an equation.
(85+x)/(100+x)=94/100
8500+100x=9400+94x
6x=900
x=150 games.
As follows:
assuming this is positive, your answer would be 9
This is because 2-3-4 is consecutive and follows the triangle inequality theorem
This is probably wrong but i'll give it a try.
The two smallest integers we have are 1 and 2...the sum of the sides would be smallest if the triangle is a right triangle, because it minimizes the third side. Then we can apply the pythagorean theorem to this:
1^2+2^2=c^2
1+4=c^2
c^2=5
c=\(\sqrt{5}\).
Then the sides of this triangle are 1, 2, and \(\sqrt{5}\). Adding them together we have 1+2+\(\sqrt{5}\)=(3+\(\sqrt{5}\)) units.
The formula for the number of terms is (last term-first term)/common difference +1. For 3, 7, 11, ..., 407, the number of terms are:
(407-3)/4+1
=404/4+1
=101+1
=102
For 2, 9, 16, .. 709 the number of terms are:
(709-2)/7+1
=707/7+1
Both of them have 102 terms.
That answer is wrong.
Yup that it correct! Great job Melody :)
The question might refer to cards with two digits, rather than cards with a number 2.
