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       5, 10, 20

1  = 20 0 0
2  = 18 1 0
3  = 16 2 0
4  = 14 3 0
5  = 12 4 0
6  = 10 5 0
7  = 8 6 0
8  = 16 0 1
9  = 14 1 1
10  = 12 2 1
11  = 10 3 1
12  = 8 4 1
13  = 6 5 1
14  = 4 6 1
15  = 12 0 2
16  = 10 1 2
17  = 8 2 2
18  = 6 3 2
19  = 4 4 2
20  = 2 5 2
21  = 0 6 2
22  = 8 0 3
23  = 6 1 3
24  = 4 2 3
25  = 2 3 3
26  = 0 4 3
27  = 4 0 4
28  = 2 1 4
29  = 0 2 4
30  = 0 0 5

pi/3 = 1.047       roof function means = 2

sqrt45 = 6.7       floor function means = 6

8^2/3 = 4              floor functionmeans  = 4           2+ 6 + 4 = 12     (????    )

Can you figure out the 2nd and the 3rd terms, then I will have a better understanding of it?

NOTE: This answer is WRONG.

So it is an example of what will not work!

Take 2 girls first     4C2

then take 5 from what is left      10C5

then multiply the answers together.

That is assuming all committee members are equal.

I never asked for a direct solution (though I wouldn't say no to it). I'm just asking if anyone can help me with it since I don't know what to do.

I mean some people just want a direct solution so...

sum/n = 80

80n = sum

(80n-100)/(n-1) = 78

80n-100 = 78n -78

-22 = -2n

n = 11

he original  total of the numbers will be    80 n

then remove one number, 100 and the average becomes 78

  the new total will be   78 (n-1)        which is 100 less than the old total  80 n

    soo   78 (n-1) = 80n - 100

             78n-78 = 80n - 100

                   22 = 2n

                     n=11

d = dave original #  =   1.3 j

dave gives away 15%   leaving 85% of 1.3j   =   (.85)(1.3)(j)

j gives away 60% leaving 40%     .4 j  left

(.85)(1.3)(j) = 282 + .4j 

1.105 j  = 282 + .4j

.705j = 282

j = 400 originally        then dave had   1.3 (400) = 520

 regular dodecahedron has 12 congruent sides.If the center of the circle is C, draw all the radii from C to each of the points P1, P2, ... P12.\Each of the triangles formed will be congruent to each other.

Consider the triangle, triangle(CP1P2).

Side CP1 = 1 and side CP2 = 1.

The central angle angle(P1CP2) = 30o.    (360o / 12o  =  30o)

Use the Law of Cosines on this triangle to find side P1P2:

     (P1P2)2  =  (CP1)2 + (CP2)2 - 2·(CP1)·(CP2)·cos( angle(P1CP2) )

     (P1P2)2  =  12 + 12 - 2·1·1·sqrt(3)/2

Find this value and multiply by 12.

https://web2.0calc.com/questions/plshelp

does this help?

See your original post for edited answer,,,,,,

When x = 3      3x^2+2 = 29

ax-1 = 29    when x = 3

a(3) = 30

a = 10

Perpindicular slope to the given line   is   -2

perpindicular line with the given point 6,2  is    y = -2x + 14

Point of intersection of the two lines is   3.6 , 6.8

point equidistant as (6,2)  on the other side of the original line = 1.2 , 11.6

Here is a graph to visualize :

https://www.desmos.com/calculator/jc8xknddvt

https://artofproblemsolving.com/wiki/index.php/2013_AMC_10A_Problems/Problem_18

This has an extremely similar question that will help you solve this:

https://www.algebra.com/algebra/homework/word/mixtures/Mixture_Word_Problems.faq.question.906125.html

Welll.... if it is a square with area 36 m²

   the sides are 6 m    original width must then  be   4 m   before you added the 2 m

      and length must have been  6 m

Angle(FHG) = 180 - 135 = 45

Angle(FGH) = 180 - 105 = 75

Angle(HFG) = 180 - (45 + 75) = 60

Angle(DFC) = angle(HFG) = 60

Angle(FDC) = 180 - 119 = 61

Angle(DCF) = 180 - (60 + 61) = 59

Angle(BCA) = 180 - 59 = 121

Angle(CBA) = 180 - (40 + 121) = 19

The measure of ABC is 20 degrees... boomer

B = pounds of B  

A = pounds of A    which equals   130 - B

5.20 (130-B)    +   (B) 4.05    =   (586.3)      solve for B

The lower dashed line is  y = -3    the graph is above it and does not include the line

    sooooo    so far     y > -3    which actually rules out the first three choices

Yeah.... people can't spend all day answering questions.

Also, EP answered your question already!

Thanks. That makes sense, but that seems extremely big!

Number of possible rolls    6 x 6 x 6 x 6 x 6 = 6⁵ =7776

Number of ways to roll   1 2 3 4 5     5 x 4 x 3 x 2 = 120

                 but you could also roll   6 5 4 3 2         = 120

total   240 ways to roll a large straight (with a single roll) out of 7776 possible rolls

240/7776 = 5/162