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Let me take a wack at this problem.

The difference between 1/4 and 1/3 is 1/12, so the sequence is increasing by 1/12 every time. Since 1/4 is the 9th term, we need to subtract 1/12, 7 times. So, 1/4 - 7/12 = -1/3

:D

This was posted before by you annd guest gave a correct answer, why did yo repost?

It got flagged right away, I posted it and it was flagged. I don't think anyone could have seen it and flagged it so quickly.

Hi, im new to web calc and just signed up, so please dont criticize me for this answer if its wrong :). (also I know very little latex so i will try to explain using words only)

First of all, the yellow balloons have to be together, so we can imagine all three as just one balloon. So, there are a total of $5!$ arrangements. But, we have forgotten that the blue balloons cant be together. There are $4$ cases in where the blue ballons are together, and we can also change the arrangements of the other $3$ ballons (because all $3$ yellow ballons are now one balloon), which is $3!$ arrangements, which is $6$, so we get a total of $24$ cases in which blue balloons are together, for a total of $96$ arrangements, which is the answer. The method which we have just used is called COMPLEMENTARY COUNTING. We calculated the opposite of what we want, and subtract it from the total amount.

Since the ballons of different colors are identical, we can't make arrangements inside of the $3$ yellow balloons. Lets say that the yellow balloons were distinguishable from one another, then we would get $3!$ more arrangements. But since that is not the case, $96$ arrangements is the answer.

(how did i do for my first answer? :D)

Maybe the moderator thinks you are not really answering the question? 

well the question asks what the solid is

Well I see you very clearly in the leaderboard because we can search you in the leaderboard and see your points to know about what place you're in

Maybe because the system got triggered by some of your keywords? By accident or something?

It has been 2 hours!!!!!!!!!!!!!!!!!!!!!!!! jeez

Triangle WXY has side lengths XY = 14 and WX = 8. The tangent to the circumcircle of triangle WXY at X is drawn, and the line through W that is parallel to this tangent intersects XY at Z. Find YZ. 

Hint:::    Use the right-angled triangle with legs of 8 and 14  

*** No matter what type of a triangle is used, the result will be the same!!! ***

Since there is a vertical asymptote of x = 3, there will be a factor of (x - 3) in the denominator.

This makes c = -3.

Since there is a horizontal asymptote of y = - 4, the ratio ax/x must be -4.

This makes a = -4.

Since there is an x-intercept at (1,0), we can look at  y = (-4x + b) / (x - 3)

and substitute 1 for x and 0 for y:  0  =  (-4·1 + b) / (0 - 3).

This makes b = 4.

f(x)  =  (-4x + 4) / (x - 3)

To get the answer to b, multiply both the numerator and denominator by 2.

Ohh, ok. Thank you so much!

Thank you!

The slope in going to be (4-1)/(-6-3)=-(3/9)=-1/3

We have an equation of y=-1/3x+b

Now, we substitute one of the points, we can choose the easier one, which is (3, 1). We now have an equation of 1=-1/3(3)+b. b=2

So the final equation is y=-1/3x+2

Correct me if I'm wrong 

This graph should help (always supposing it's visible!):

You are trying to find functions that satisfy the relationship:  g(x)*g(y) = g(x+y) + x*y

Pretend I defined the function as  g(z) = z + 1.

When z = x we have  g(x) = x+1

When z = y we have  g(y) = y + 1

When z = x+y we have g(x+y) = x + y + 1

So this definition of the function g satisfies the specified criterion.

I suspect its the only one, but I haven't attempted to prove it!

Area = base x height for a parallelogram    base = 14

find height     sin 45 = h/10      solve for h    then   area  =   14 * h

/Bump

(4x+3)(x-8)+(x-5)(4x+3)=0

4x^2 - 32x  + 3x - 24     +     4x^2+3x-20x-15

8x^2 -46x-39 = 0    Quadratic formula shows x = 6.5   and   - .75

This involves systems of equations. To do this, let's first set up our equation:

x + y = 6

xy = 3

We now can see that x in terms of y is 6-y

Plug that in for x in the second equation, and you get 6y-y^2=3. We can turn this into a quadratic and solve.

-y^2+6y-3=0.

Divide both sides by -1

y^2-6y+3=0

Now, can you solve the quadratic? 

Once you have done that, find x, and then you are all set!

What kinds of keywords? It was moderated as soon as I posted it

Hmm maybe.

Thanks, I got it!

Sometimes I think there's keywords that trigger moderation, or someone just reported you.

Thanks so much for the response. I understand everything past the first step, but I'm not exactly sure how you got there. How did you know that g(x)=x+1 and that g(y)=y+1? Thanks again.

Hmmmm....   I do not have any of the numbers ending or starting with zero..... Only the middle number can be zero in my answer....

   I still find 60 numbers.....   can you explain further?

Wait a minute.....I found my error ....I edited my answer above.....I mistakenly listed 4 as a possible, when I should have only counted down to 5   ...just a math error in my post....  THANX !

9 n 5    -   5 n 9

8 n 4  -  4 n 8

7 n  3 -  3 n 7

6  n 2 -  2 n 6

5 n 1   - 1 n 5        'n, can be any  0-9       so  5 x 10 = 50