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2\9-(-4\3+7\8-2) =

2/9 + 4/3 -7/8 - 2 =

17/72   +   96/72    -   63/72   -  144/72 =

(17  +  96  - 63  - 144) / 72                                 take it from here !

Nope! I just needed help on the same question. NerdyKid posted the question almost two years ago, and I just discovered the site over summer of 2020, so yeah..

Just flip it: 4/3 to 3/4 

i got it now, thank u so much!

area=36

The only positive integers that balance the equation are:

x = 216 + 27 + 8 + 1 = 252

74_9  +  77_9 = 162_9

7_9  -  4_9 = 3_9

n^3 = (n-1)^3+(n-2)^3+(n-3)^3.

I could only find one value for n:

n = 6

6^3 = 5^3 + 4^3 + 3^3 = 216

5x = 3.5 * 13

x = 9.1        AB = 16.5          CD = 14.1

pretty sure u are darren

As follows:

Hi Happy,

Are you also Nerdykid ?

If you gave your question an appropriate heading you would greatly increase your chances of an appropriate answerer seeing it and responding.

Im pretty sure this person is taking the same exam as me. 

No the question is correct 

Yes it is very weird

A line passes through A(3, 7), and B(-4, 9). Find the value of a if C(a, 1) is on the line.

a = (7 - 1) / arctan(2 / 7) + 3 = 24

1. For a triangle XYZ, we use [XYZ] to denote its area.

Let ABCD be a square with side length 1. Points E and F lie on line BC and line CD, respectively, in such a way that angle EAF=45 degrees If [CEF]=1/9, what is the value of [AEF]?

[AEF] = 4/9

Is it \(3\sqrt{\frac{13}{3}}=\sqrt{39}\)?

Obviously, it is less than (not equal to). We just need to find the equation of the line then, has y-intercept of -2. So y=mx-2 --> -1=5m-2 --> m=1/5. So y=1/5x-2 --> y-1/5x+2=0. Less than, so y-1/5x+2<0

Save rite --> 5.25*5=26.25

Spend less --> 7.50*3=22.50

So 22.50<26.25 --> Ans = 22.50

\(x^2+7x-44=(x+11)(x-4)\). So \((x-4)(x+9)=x^2+5x-36\rightarrow a=-36\). And \((x+11)(x-6)=x^2+5x-66\rightarrow a=-66\). So \(\boxed{a=-36,-66}\)

\(x-3\ne 0\rightarrow x\ne 3\). Also, \(2x-5\ge 0\rightarrow x\ge 5/2\). So domain is \(x\ge 5/2, x\ne 3\). For range, it is simply all reals.

First of all, x-7/=0 --> x/=7. Also, 7(x/(x-7))/=6 --> 7x/=6x-42 --> x/=-42. So \(\{x|x\in\mathbb{R}, x\ne 7, x\ne -42\}\)

slope is (9-7)/(-4-3)=-2/7. So y=-2/7x+b --> 7=-2/7*3+b --> b=55/7. So y=-2/7x+55/7 --> when y=1 --> 1=-2/7a+55/7 --> a=24

To solve this problem, you actually don't need to know the cone formula! This is simply the Pythagorean Theorem. 

Using the theorem, which is  \(a^2+b^2=c^2\) , we can insert our variables into the equation. Since \(c^2\) is the hypotenuse of the triangle, 12 will be our \(c\). 

\(h^2+6^2=12^2\)

\(h^2+36=144\)

\(144-36=h^2\)

\(h^2=108\)

\(h=\sqrt108=6\sqrt3\)

So, the height of the cone is \(6\sqrt3\) cm. 

Hope this helps!

Doggo

b=10-a

c=a+90

when simplified

a+2b+c=110

a+2b+c=110

a+3b+2c=110+10-a+a+90

That's 210.