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This number's prime factorization is

3^3 × 5^2 × 7 × 17

Anythiing higher than 1! will require a 2, but there is no two, and you're blatantly denying "1",

so...

Other than 1, I see no solution.

Take prime factorization of this number.

For instance, if you get, 2^49 x 3^39 x 5^10

5! =

2^1 x 3^1 x 2^2 x 5^1, etc etc.

You could use that.

Sorry, this is very difficult to read. When you copy your problem in, and for the blank spaces where latex goes, please just type in the letter/character.

Well it never said it can't be two digits

There isn't one.  I tried brute force.  I divided 80325 by every n! starting at 1! and continuing through 8!.  None* of them worked.  The only possible answer is 1 and you've already dismissed that, so I don't know what to tell you.  Maybe you copied the question incorrectly.  

*Actually, they all divided into 80325.  The problem doesn't state that the quotient has to be an integer, but in problems like this it is implied.

_.

Hi!

Well, if the pattern goes in that order, and there are 74 beads, then we can first see how many times we can repeat that pattern in the necklace.

74/6=12.3333333333333(repeating)

So we can do that pattern 12 times.

12x6=72

After we do that pattern 12 times, we have 2 beads left over, so the first two beads of the pattern will be placed. The second bead should be orange. (First bead red, second bead orange).

Hope this helps!

6 quarters gives you $1.50  

9 nickels    gives you $0.45   

total amount                $1.95    

Well, ok... the only answer I can think of and prove that fits all the criteria is 1. Sorry I can't be of more help.

no, this is not. It is a practice question. I have done a lot so my score is really high. There higher the harder

...wait this is a homework problem...

...homework problems aren't supposed to be put here or answered here.

... I thought this was like a for fun problem on a website or something...

...

I would, but if I get it wrong it would cost me a lot....

I mean, 1! is still 1, and every number can be divided by 1. Also, 1 is positive, and the LEAST positive integer there is. It fits the criteria, but I can agree with you that it seems like a "too easy" answer to the problem. Maybe you could try it?

No, I don't think that woud work

Wouldn't it be 1? If you're looking for the least positive integer that when factorialed divides 80325, then I think 1 fits the bill.

hmmn nope

Try 17!

Anyoneeee?

Please help asap! is it green or yellow? please help!

The answer you gave was wrong but i figured it out myself, the actual answer is 55

q(-1) = 18.

Tne sum a + b + c + d + e is 28*5 = 140.

Hi!

This is a double equation thing(I don't know the name)

Let x = number of tarantulas

Let y = number of frogs

If frogs have 4 legs and 2 eyes, and tarantulas have 8 legs and 8 eyes, then we can set up two equations, one for the legs and one for the eyes.

For the eyes:

8x + 2y = 80

For the legs:

8x + 4y = 104.

Now, we combine the equations.

8x + 2y = 80

-

8x + 4y = 104

------------------------

-2y = -24

/-2        /-2

-------------------

y = 12

y represents the number of frogs, so there are 12 frogs.

I think you can take the rest from here. :)

Hope this helps!

Exactly 24 only. Here is the computer code that listed them:

n=1; b= 475; c= n/475;printc,n;n++;if(n<=474, goto2, 0)

OUTPUT = 24 such numbers, from 19 to  456 [All multiples of 19 between 19 and 474]

Good work.