n √n = 4 √2
n^(3/2) = √32
n^(3/2) = 32^(1/2) square both sides
n^3 = 32 take the cube root of both sides
n = 32^(1/3) = (8 * 4)^(1/3) = 23 √4
No Thats the answer to 2sqrt 4 this is 4 sqrt 2
Cross multiply
5n = 8n+24
3n = -24
n = -8
n3/2 = 4
n = 42/3 = 2.5198421
Thanks ya'll! Have a great day!
We have a horizontal asymptote at y = -1
This means that the ratio of the coefficients on the x variables are
1 / B = - 1 → B = -1
Since we have an x intercept at 4....this implies that 4 + A = 0 → A = -4
And finally, since we have a vertical asymptote at x = 3, this means that
-1(3) + C = 0
C = 3
So...our function is
x - 4
_____
-x + 3
A + B + C = -4 -1 + 3 = -2
Sum of the interior angles of a polygon = (n - 2) (180) where n is the number of sides
So we have this
(n -2) (180) = 160 + 146 (n - 1) simplify
180 n - 360 = 160 + 146n - 146
180n - 360 = 14 + 146n
180n - 146n = 360 + 14
34n = 374
n = 374 / 34 = 11 sides
We can use the exterior angle theorem here
An exterior angle of a triangle = the sum of the measures of the two non-adjacent interior angles
So we have that
75 = 47 + angle we are looking for
28° = angle we are looking for
5 (3x + 2) - 2 = -2(1-7x) distribute the 5 and -2
15x + 10 -2 = -2 + 14x simplify
15x + 8 = -2 + 14x
15x -14x = -2 - 8
x = -10
How many integers "n" can be used such that the quantity abs[2n^2+23n+11] results in a prime number?
n =0, -10, -12 gives the following prime numbers =11, 19, 23
how about - pi
Find the number of square units in the area of the shaded region.
Hello Guest!
\(A=12cm\cdot 4cm-\frac{1}{2}\cdot 9cm\cdot 4cm\\ A=48cm^2-18cm^2\)
\(A=30cm^2\)
The number of square units in the area of the shaded region is 30.
!
GCD of all elements of S, or all Pythagorean triples is always = 1
a + b = 7.
There are 106 different orders.
One angle is 47 degrees the second angle is 180 - 75 degrees
the third angle will be 180 degrees minus the two angles ......
The binomial squared must be in the form \((\sqrt ax+3)^2\)
When expanded this is \(ax^2+6\sqrt ax+9\) which means that \(6\sqrt a=16\) or \(a=\frac{64}{9}\)
slope m = (-16-5)/(-3-5) = 21/8
y = 21/8 x + b sub in either of the points to calc 'b'
5 = 21/8 (5) + b so b = -65/8
y = 21/8 x -65/8
Various multiples of pi/4 make sin2(x) - 1/2 = 0. However, none of these result in x being an integer!
If the question is restricted to real numbers, then the argument to the log function must simply be positive. In this case, log(sin2(x)-1/2) is ok for x = 1 and 2, but is complex for x = 3, so x = 3 would be the smallest positive integer.
20 = 5/9 (f-32)
20 * (9/5) + 32 = f
Thank you!
вот задача, я ее должен прописать, как формулу в Excel
a=1; b=1;d=a+b;f=gcd(a,b)+lcm(a,b); if(d==80, goto5, goto6);printf, a, b; a++;if(a<200, goto2, 0);a=1;b++;if(b<200, goto2, discard=0;
a = 39, b = 41
a + b = 39 + 41 = 80
GCD(39, 41) = 1
LCM(39, 41) =1599
GCD + LCM =1 + 1599 =1600
!
вот задача, я ее должен прописать, как формулу в Excel
