sorry I meant
Rick is thinking of a positive factor of 14 and Steve is thinking of a positive factor of 42. If Rick and Steve are thinking of the same number, how many possible numbers could they be thinking of?
Its not The first 0.02 is a repeating decimal
it is 0
let's say A=0
987,654,320/7 = 141093474.286
the .286 represents that we are 1 - 0.286 = 0.714 off from making 987,654,320 to be divisible by 7 wholly, therefore:
987,654,320 + 7 * 0.714 = 987,654,325
Just try 0 divide by 7 if not try 1 divide by 7 if not try 2 divide by 7 if not......
(if it is 0 1 2 there will be a second one that will work)
∑[1/(5^n), n, 1, ∞ ] = It converges to 1 / 4
6w/5b * 3b/11f *110f = 36 w
покажите как вы это в экселе написали. Панель куда задачу написали, скрин сделайте.
Smallest 4 digit base 8 number = 1000 = 51210 = 2002223
Largest 4 digit base 8 = 1111 = 58510 = 2102003 I think you can count 'd' now.....
The legs form two altitudes = 5 and 12
The remaining altitude drawn from the right angle to the hypotenuse = (product of the legs) / hypotenuse =
(5 * 12) / 13 = 60/13 units
Sum of the altitudes = 5 + 12 + 60/13 = ( 17 * 13 + 60 ) / 13 = 151/13 units
"least common factor of 8 and 14, which is 80" No, it is not.
Write out the list of primes that are less than 20 ...easy-peasy
Put the two largest ones in the numerator
Put the two smalles ones in denominator.....do the math...done!
B = 60°....AC = 7 √2
A = 30° ....BC = 7 √2 / √3 = (7/3) √6
C = 90° .....AB = (14/3) √6
Perimeter = [ (7/3 + 14/3) √6 + 7 √2 ] = (21/3) √6 + 7 √2 = 7 √6 + 7 √2 units
Since 6 = 2 x 3, then the greatest power of 3 when factoring 100! =48. And since 2 has power of 97, then 6^x =[2^48 x 3^48] = 6^48.
100!= 2^97 * 3^48 * 5^24 * 7^16 * 11^9 * 13^7 * 17^5 * 19^5 * 23^4 * 29^3 * 31^3 * 37^2 * 41^2 * 43^2 * 47^2 * 53 * 59 * 61 * 67 * 71 * 73 * 79 * 83 * 89 * 97
x = [100 / 3 + 100 / 3^2 + 100 / 3^3 + 100/ 3^4] = 48
x^37 mod 527=490, solve for x
a=1; c=a^37 % 527; if(c==490, goto3, goto4);printc, a; a++;if(a<1000, goto1, 0)
x =527c + 56, where c =0, 1, 2, 3........etc.
The smallest x = 56, and 56^37 mod 527 =490
2 ( 4 + 5 + 6 + 7 + 8) + 7(5) =
60 + 35 =
95
The degree of the polynomial in the numerator > the degree of the polynomial in the denominator
This series will diverge
(d) is correct
Oops....let me fix that !!!
2) Note that
9 * 8 = 72
So ceiling 8.... = 9
And floor 8..... = 8
This indicates that the solution is
( 8 < h < 9 )
Thanks so much for all the help. I read your solution and I think you did everything great exept you kinda got a and b mixed up.
(1) Note x^2 - 1 = (x - 1) (x + 1)
x + 2 A B
____________ = _______ + _____ multiply through by (x - 1) ( x + 1)
(x - 1) ( x + 1) x - 1 x + 1
x + 2 = A ( x + 1) + B ( x - 1) simplify as
1x + 2 = (A + B)x + (A - B)
Equating terms we have that
A + B = 1
A - B = 2 add these equations
2A = 3
A = 3/2
And
3/2 + B = 1
B = -1/2
CORRECTED ANSWER !!!
I don't think that there is an interger x that satisfies x^37=490. The closest integer would probably be 1. Hope this helps!!
Common ratio , r, is -12/48 = (-1/4)
Sum of an infinite series =
first term 48 48
_________ = _______ = ____ = 48 ( 4/5) = 192 / 5
1 - r 1 - (-1/4) (5/4)
Thanks Everyone!!! :)
