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1/9

Becuase if you add all the balls you get nine,

then i subtracted the red balls from the blue balls to get one

so all the balls together are the deniminator and the red balls subtracted from the blue balls are the numerator! 

Answer=1/9

Also...isn't the entire purpose of this website asking for homework help?

1 bush / 8 con *  5 con / 2 zuc   * 48 zuc

= 1/8 * 5/2 * 48 = 15 bushes

.75 = 3/4

33 3/4       

a box has a width (x), where (x) is prime. If the box has a height of (x+2), and a length of (x-1), and volume is 140, what is (x)

Hello Guest!

\(V=w\cdot h\cdot l\)

\(400=x\cdot (x+2)\cdot (x-1)\\ (x^2+2x)\cdot (x-1)={\color{red}(400\ not\ correct)}\ 140\ (excuse\ me,\ please!)\\ x^3-x^2+2x^2-2x={\color{red}(400)}\ 140\\ x^3+x^2-2x-{{\color{red}(400)}\ 140}=0 \)    

With x = 5, the volume of the box is 140.

  !

Thanks Pangolin14,

I am really pleased that you have interacted with me.   

I am just going to look at the  2,1,1,0 arrangement

I do not understand how you are looking at the problem.

I see 12  arrangements of bracelets and 12 arrangements of people =144

but then for some reason, you double your answer ... I do not understand why.

Here is my logic,

FIRST assume all the bracelets are the same.

I am going to order the people so that the first person in the queue gets 2 bracelets, the next two people get 1 bracelet each and the last person gets no bracelets.

There are 4! ways to order 4 people.  but it does not matter what order the middle 2 are in because they are both going to get 1 bracelet anyway so I have to divide by 2.

4!/2 = 12 ways

Now how many ways can I queue the bracelets?  that would also be 4!

BUT it does not matter what order the first two are in because they are going to get given to the same person.

so that is

4!/2 = 12 ways

So I am reasonably confident that the answer is 12*12 = 144 ways

Answers: 6.084 for (a), 2.721 for (b)

Generally, \(\log_a x\cdot y = \log_a x + \log_a y\). So log_a (5 * 7) = log_a (5) + log_a (7) = 2.935 + 3.149 = 6.084

Next, log_a (5*5) = log_a (5) + log_a (5) = 2.935 + 2.935 = 5.87. Then \(log_a {\frac{x}{y}} = log_a x - log_a y\). So log_a (25/7) = log_a (25) - log_a (7) = 5.87 - 3.149 = 2.721. Log rules are very important :)

You are very welcome!

:P

Never mind... it took me many hours of frustration and wanting to punch myself for being dumb [I said 144/2 was 77 (T_T)], but I got every part! If you see this, no need to solve!

Answer: 1

\(3Y 2\) means that a = 3 and b = 2.

Then, we can plug in and solve. 3^2 - 2 * 3 * 2 + 2^2 = 9-12+4 = 1.

You are very welcome!

:P

Initial temperature of the soup is when t = 0

76 + 105 e^{-0.125 (0)} =  76 + 105 = 181 degrees F

After 30 miutes:

76 + 105 e^-0.125(30)  = 76 + 2.47 =78.47 degrees F    

f(0)  = a (0^2) + b(0) + c  = 0      shows that c =0

f(1) = a(1^2) + b(1) =1      so      a + b = 1 

f(2)  = a(2^2) + b(2) = 5    so    4a + 2b = 5

                                               solving these two equations results in a = 3/2   b = - 1/2

f(x)  = 3/2  x^2    -1/2 x 

f(3) = 3/2 (3^2)  - 1/2 (3) = 12

Someone already posted this one today...and it was answered by a guest.....see if you can find it.

Sorry about that!  For some reason, I read ΔBCD as ABCD. 

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

BC = CD = 5√6          ∠CBD = ∠BDC = 45º          ∠ADB = 105 - 45 = 60º

BD = 10√3            AD = cos(60º) * 10√3 = 5√3

AC = 16.73  

Again, sorry if the way I came through was harsh..I was just really stressed because I don't get help with any of my homework. My teacher posts things wwithout teaching us it, and I was just trying to get some help from the community.

Angle CBA =75 degrees
Angle CBD =45 degrees
Angle DBA =30 degrees

By Pythagoras
Side AD =5sqrt(3)
Side AB =15
Side BD =10sqrt(3)
Side BC =5sqrt(6)

Using Law of Cosines:
Side AC =16.73

With all due respect, I'm not trying to make a scene. I've gotten good grades all by myself for the rest of the quarter, I was just asking a FEW questing to clear things up. You can call me names all you want, and I'm sorry if I offended you before but all I wanted was a little reassuring because my parents don't help me, let alone my teacher. I can't do it by myself because I don't understand, so the next people I turn to is the "nice" comunity online.

Sorry Snowflake....that doesn't fly with me.....

   there are several serial  postings of similar questions ...I expect all by YOU.   YOU have not tried to answer any of them. YOU just post them here and expect someone to give you the answers.....how is that YOU getting a good grade?  YOU didn't do...or attempt to do...or attempt to learn how to do the problems yourself.  Further , YOU have not even acknowledged those who took the time to help you or give you the answers you entitled little punk.  All you do is whine and make excuses .  

   Soooo.......step down off of your little soapbox and put a little effort into YOUR grade !!!    

Please be careful when you are answering, ABD is not half of 105 degrees and AB≠AC.       

slope of given line = 3    this is the same as the parallel line

point slope form

(y-1) = 3(x-2)       re-arrange

y-1 = 3x-6

y = 3x -5

A  put 5 in for t   and compute   40 e ^(-.087)(5)  = .........  gms

B  put 10 in for A(t) and compute    10 = 40 e^(-.087)(t)      and use your calculator to  solve for t

1 000 = 600 e^2k

k = .539927

10 000 = 600 e^{.539927 t}    where t = days

10 000 / 600 = e ^{.539927 t}

t = 5.21 days    to 10 000 bugs

Can you maybe just shut up then? I did try to do them but our teacher never taught us this and expects us to do it. I do try, just for your information. He just posted this homework today and we have daily homework. Please don't assume what I do just because I'm desparate for help and want to get a good grade because of a lousy teacher.