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Thanks for pointing that out guest...

98/18 or 49/9

Angle A = Angle B

56  - 3a =   8a + 1    rearrange as

56 -1  = 8a + 3a

55  = 11a

Dived both sides  by  11

5  =a

So angle  B  =8(5) + 1 =   41° 

We know that angle D  =107°

Therefore, angle C   = 180   - 107    - 41   =   32°

f(x)  =(2/3)x^3  -1

y= (2/3)x^3   - 1

get x by itself...."swap"  x and y

add 1 to both sides

y + 1  = (2/3)x^3     mutiply both sides by    3/2

(3/2)y +3/2   = x^3           take the  cbe root of both sides

∛ [ (3y + 3)  / 2  ]   =  x

Inside the radical, nutiply numerator, denominator  by 4

∛ [ (12y + 12)  / 8  ]   = x

∛ (12y + 12)  / 2      =  x      "sap  x and y

∛ (12x + 12)   / 2   =  y   =   the nverse 

MooMoo, 7 • 14 = 98.   Not 91.  

_.

18/14 equals 7/x.

Cross multiplying we get 91=18x

x=91/18

1. d = 1 + 2i

2. a = 1 - i

3. T_3 dilates by a factor of sqrt(3)/2.

2x^2 + 6x + 11

2 (x^2+3x)    + 11

2(x+1.5)²  - 4.5 + 11

2 (x+ 1.5)²  + 6.5

y=2/3x^3-1    change x's and y's

x = 2/3 y^3 -1  solve for y

 y =   cubrt [3/2(x+1)]                   this is y^-1

2(x+1.5)^2+6.5

(a+b)^2=a^2+2ab+b^2

(x+1.5)^2=x^2+3x+2.25

Times 2

2x^2+6x+4.5+6.5=2x^2+6x+11

h is 1.5

In triangle ABC show above, cos B = 6/10. What is tan C?

Hello Guest!

\(c^2=a^2+b^2-2ab\cdot cos\ C\\ cos\ C=\dfrac{a^2+b^2-c^2}{2ab}\\ cos\ C=\dfrac{49+32-25}{56\cdot \sqrt{2}}=\dfrac{1}{\sqrt{2}}\)

\(C=\arccos\ \dfrac{1}{\sqrt{2}}\)

\(C=45°\)

\(tan\ C=tan 45°\)

\(tan\ C=1\)

  !

f(6) would be -1/6

doing that again gives us -1/(-1/6) or 6 again.

So every two times we use the function they cancel each other out.

So the first four functions are ignored

So all we have is f(6) as the answer

The way to choose two types of cheese - 8*7/2 or 28

28*10 is 280

Solve 1/3*t - 5 < t - 2.

Hello Guest!

\(\frac{1}{3}t - 5 < t - 2\)   |+2

\(\frac{1}{3}t-3 < t \)  

\(t\in \mathbb R\ |\ t\leq-4.5\)

  !

WOW!  If they cannot solve  4 x 8 x 20 = ______cm³       They need more than help !!!!

1/p + 1/q = 1     multiply by pq to get

q + p = pq             so p+ q = 9 too

x² +12x + 9     take 1/2 of the x coeff

(x+6)²    + 9  - 36

(x+6)² -27   

R(1 - 2i) = 1 + 2i, so |R(1 - 2i)| = sqrt(5).

2A = 13.

There are no solutions.

steps: 

1. distribute. 

2. subtract 6x from both sides. 

3. subtract 12 from both sides to get 0=-10 which obviously isn't true

so there are no solutions. 

That's not correct. :(

Shouldn't there be 4, since the power of x is 4?

Oh. I misread my own post. :P I though 350 was included. Sorry. :(

it was 49

Here's an answer without computer programming. 

first, find the prime factorization of 350. (2*5^2*7)

then we need to find all multiples of 7 that are between 1 and 350. 

Solution 1: Count.

7 14 21 28 35 42 49 56 63 70 77 84 91 98 105 112 119 126 133 140 147 154 161 168 175 182 189 196 203 210 217 224 231 238 245 252 259 266 273 280 287 294 301 308 315 322 329 336 343 350

There. Now we count the numbers. After counting, you see that there are 50. 

Solution 2: Find what is the first multiple of 7/350. 

The first multiple of 7 between 1 and 350 is 7. so 7/350=0.02. 

Then, drop the two zeros and find out what is 100% (1 whole, ignoring the percent) /2. 

Then, we get 50. 

Also, @Guest is wrong. 

@Guest: yeah. Also, your answer 1, 2, 3 is correct. Are there any more? 

The formula that you would use for this would be \(l *w * h\) where \(l\) and \(w\) are the dimensions of the base and \(h\) is the height of the rectuangluar prism, or how tall the container is. 

Plugging the numbers into the formula, we get:

\(4cm * 8cm * 20cm\)

Solving this, we arrive at the answer of \(640cm^3\). (It would be cm^3 because this problem is asking for the volume. Think 3 for 3D.)

Hope this helps!!!

:)