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Don't really need the  Q formula

-6t^2  +  83t    -77   = 0             factor

(-6t  + 77)  ( t - 1)  =   0

Set each factor to 0  and solve for  t

-6t  + 77  = 0                             t  - 1     =  0

-6t  = -77                                    t   = 1  (second)  =  time  to  first reach 77 ft

t =  -77/-6  = 77/6 sec

See https://web2.0calc.com/questions/ep-melody-cphil-please-come.

Thanks!

x + ( x + 1) + (x + 2) + (x + 3) + (x + 4)  =  105

5x +  10  =   105

5x   = 105   -10

5x =  95

x  =  95/5   =   19

The  numbers are

19, 20, 21, 22, 23

Median =   21

Mean =  105/5   = 21

Median  - Mean    =   0

-4x -   15y   =  -17

4x  +  5y   =    -13

A    add  these and we get that      -10y   = -30

B    -10 y   = -30

             y =  -30/-10   =  3

C      4x  +  5(3)   =  -13

D        4x + 15  =  -13

           4x  =   -13   -15

            4x   = -28

              x =  -28/4   =  -7

E   (x , y)  = (   -7 ,  3)

thank you i got it!

a) 3/4

b) $200

c) $600

Ten people at the party and each mus shake hands with eight other people   BUT each hand shake involves two people

     10   *       8     / 2 = 40 handshakes should cover it.

y =5x  -7

-3x  -2y  = -12

a)   -3x - 2( 5x  -7)   = -12

b)  -3x - 10x  + 14    =  -12

-13x  =   -12   - 14

-13x =   -26          

x = -26 /  -13  =     2

c)   y = 5(2)  -  7   =    10  - 7     =  3

d) ( x , y)   = ( 2,3)

y = 77

77 = -6t^2 + 83t

-6t^2 + 83t - 77 = 0    now use Quadratic Formula to solve for 't'

                       you will get two answers for t...one is for the projectile going up (the smaller 't' obviously) and the other is on the way down

a = -6   b = 83     c = 87

\(t = {-(83) \pm \sqrt{(83)^2-4(-6)(87)} \over 2(-6)}\)

x -3x+1      'complete the square'   by taking 1/2 of  -3

(x-1.5)²   -2.25 +1

(x-1.5)² - 1.25                   Take it from here.....

here are tow sides that are   14 x 8

  and two sides that are         10 x 8

2 (14*8) + 2(10*8) = 384 ft ²

384 ft²  /   250 ft² / gal  =  1.536 gallons needed

Every week, Josie will do 2 more tests than Dustin. 

He's 8 behind so he'll need 4 weeks. 

4*3 + 3 = 15

In 4 weeks, the children will have each passed 15 test. 

I hope this helped. :)))

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50 grams * 30 %  = 50 * .3 = 15 grams cocoa in the 50 gm bar

(14+10)*16 = 384. 

384/250 = 1.536

So he needs 1.536 gallons of paint. :)))

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ITS  50

GRAMS

Being aware of the triangle side length rule  (any two sides' sum must be greater than the third side)

  135 would not work  as 1+3 is not greater than 5

3 5 7    will work      perimeter = 15 units

Hi Guest!

1001 prime factorzation is 7*11*13.

GCD that are possible and 2 digit is 11, 13, 77, and 91. 

So 11 has the numbers: 11, 22, 33, 44, 55, 66, 77, 88, and 99: or 9 numbers. 

And 13 has the numbers: 13, 26, 39, 52, 65, 78, and 91: or 7 numbers. 

Total there are 99 numbers, and 9+7+1+1 have double digit gcds. 

So the answer is 99 - (9+7) = 83. 

So the answer is 83. 

I hope this helped. :))

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no clue

First courier charge 18  + w       where w = pound weight

Secind courier charge = 8 + 2w        where are they equal?

18+w    = 8 + 2w

10 = w                              ten pounds

cost will be   8 + 2(w) = 28 dollars

This is just a pythagorean theorem question for a right triangle with legs of 8 and 6 km      what is the hypotenuse?

Hypot²  = 8² + 6²

hypot = sqrt (100) = 10 km

The latex got the Q a bit messed up....I assume the company pays flat fee 120 for rental and $3 for supplies for each antendee

the atendees pay $ 15 ea

120 + 3x = 15 x    solve for x

120 = 12x

x = 10   

At 15 atenddees expenses will equal revenues    120 + 3(10) = 150

2 * r = 1/5     means

r = 1/5 ÷ 2 = 1/10

2    1/5     1/50    1/500   1/5000

or   2 * (1/10)⁴ = 2 * 1/10000 = 1/5000

 a mod 3 = 2
a mod 5 = 4
a mod 7 = 1
a mod 9 = 8, solve for a

a =315n + 134, where n=0, 1, 2, 3,........etc.

When n= 0, the smallest "a" ==134

Hi Guest!

5.75(p) - 3.25 = c

If he buys 5 pounds, we just replace p with 5. 

5.75(5) - 3.25 = c

c = 25.5

I hope this helped. :)))

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