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+118724

+2

Help please!! Graph f(x)=3sin(1/2x)−5. Use 3.14 for π. Use the sine tool to graph the function. The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.

See if this helps.

https://www.desmos.com/calculator/ual0qhrsqh

Here I have built the function starting with the parent graph of

step 1: f(x)=sinx

wavelength = 2pi

The graph is on the centre line at (0,0)

the centre line is y=0

Amplitude (hight from the centre line) =1

With each step click on the little circle to the left of the graph to make the graph visible.

step 2: f(x)=sin(x/2)

the only thing that has changed is the wavelength

It was 2pi now it is TWICE that. so it is 4pi

Nothing else has changed.

Step 3: f(x)=3sin(x/2)

The 3 will change the amplitude, ao amplituce is now 3.

Nothing else changes

Step 4: (x)=3sin(x/2) - 5

this drops the graph 5 units so that the centre line become y=-5

Nothing else changes.

Now I have built the graph that you want from the parent function f(x)=sinx

Please make an effort to understand what I have done.

You will need to play with the graph a bit.

Getting used to Desmos graphing calc will be an invaluable tool for you anyway.

You can finish the question for yourself now.

MelodyJan 26, 2021

#2

+539

+1

Say the number of balloons in a small bouquet is x and the number in a large bouquet is y.

The equations we have are

7x+8y=193 and

8x+2y=92.

On the second equation, isolating y we get 2y=92-8x or y=46-4x.

Plug that in our first equation to get

7x+8(46-4x)=193.

7x+368-32x=193

-25x+368=193

-25x=-175

x=7

Now that we have x, we can solve for y.

8(7)+2(y)=92

56+2(y)=92

2(y)=36

y=18.

MooMooooMooMJan 26, 2021

#1

0

Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.

One Friday night, two large groups of people called Livingston Taxi Service. The first group requested 1 sedan and 2 minivans, which can seat a total of 16 people. The second group asked for 3 sedans and 2 minivans, which can seat a total of 24 people. How many passengers can each type of taxi seat?

A sedan can seat ___ people, and a minivan can seat ___ people.

GuestJan 26, 2021

#1

+2406

0

Hi GR0001!

10(e - 4) = 20(f - e)

10e - 40 = 20f - 20e

e - 4 = 2f - 2e

3e = 2f + 4

20(f - 4)=10(e+f)

2(f - 4) = e + f

2f - 8 = e + f

f = e + 8

3e = 2(e + 8) + 4

e = 20

f = 20 + 8

f = 28.

So e = 20 and f = 28.

I hope this helped. :)))

=^._.^=

catmgJan 26, 2021

#1

0

Hello,

Isn't it just n = 4? Because the denominator is 32 the nth term must be 1/32 (you can check this yourself.)

Also if anyone wants to take the time out please answer my question here: https://web2.0calc.com/questions/please-help_81768 (I don't know if this is soliciting if it is then sorry.)

Hope that helps!

GuestJan 26, 2021

#1

+1

Hello,

Since with each step you are only going down or right (not backwards) you need to travel a total distance of 6 down and 4 right. So this question is basically asking, "How many distinct ways are there of arranging 6 stars and 4 bars?" So I think the answer would be 10 choose 4 = 210 ways using stars and bars (you may want to look that up yourself.)

Also if anyone wants to take the time out please answer my question here: https://web2.0calc.com/questions/please-help_81768 (I don't know if this is soliciting if it is then sorry.)

Hope that helps!

GuestJan 26, 2021

#1

0

I think that is supposed to be 93 * P^2/3

^{P = 1 for Earth Making D = 93 million miles for Earth}

For Pluto D = 93 (248)^2/3= ~3671 million miles from the Sun

GuestJan 26, 2021

#6

+118724

0

Thanks Alan :)

MelodyJan 26, 2021

#2

+506

0

Nice answer guest, but I don't think it's correct. Here's why:

Since AD is parallel to BE, Angle BEC = Angle ADC, and therefore, in order for Angle CAD to equal angle CBE, triangles BEC and ADC must be similar to each other. That can only happen if angle BCE = angle ACD, and that can only happen if A is on BC. Since that isn't allowed, angle CAD cannot be equal to angle CBE.

textotJan 26, 2021

#1

0

A box has a total surface area of 100. The length of the box is equal to twice its width, as well as equal to 8 less than its height. What is the height of the box?

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Width = 1w Length = 2w Height = 2w + 8

(w * 2w) + w(2w + 8) + 2w(2w + 8) = 50 w = (-3 + √34) /2

Height = 2w + 8 ≈ 10.831

GuestJan 26, 2021

#2

+73

+6

thx so much!!! ❤

VanillaJan 26, 2021

#5

0

if it goes down .13 (which is 13 %) ....you have 87% left .....which is .87

GuestJan 26, 2021

#7

0

Nope.....why would I? The question asked for 5666/2381 ......I gave the answer. D'Oh!

GuestJan 26, 2021

#1

0

The equation f(f(x)) = 3 has one solution.

GuestJan 26, 2021

#1

+1

Prime numbers less than 25

2 3 5 7 11 13 17 19 23

17 5 3

GuestJan 26, 2021

#2

0

*** error ****

Ava was walking for an hour before her father left to pick her up..... then another 6 minutes when he picks her up and drives home

1 hour 6 minutes

GuestJan 26, 2021

#1

0

A cup is 8 ounces

you have

3 gallons x 128 oz/gallon = 384 oz

plus 6 bottle x 64 oz/bottle = 384 oz

total 768 oz

768 oz / 8 oz/cup = 96 cups

GuestJan 26, 2021

#1

0

George cut 12 minutes off of his usual rountrip time...so Ava was walking for 6 minutes

GuestJan 26, 2021

#2

0

it's wrong ;-;

GuestJan 25, 2021

#1

0

Both of the other angles must be 45^o so each leg is the same length

pythag theorem 6^{2 =}L² + L²

36 = 2L²L = sqrt (18) Area = 1/2 b * h = 1/2 (sqrt18)(sqrt(18) ) = 9 in ²

GuestJan 25, 2021

#1

0

40 % off means the price is 60% of original

.6 x = 16

x = 16/(.6) = $.........

GuestJan 25, 2021

#1

+1

KE = 1/2 mv²

690000 = 1/2 (.16)v²

sqrt [690,000 *2 /(.16) ] = ........ m/s

GuestJan 25, 2021

#6

+122

0

Good Job! Great start to your web2.0calc journey!

cryptoaopsJan 25, 2021

#5

+122

-1

$\mathrm{Write\:the\:problem\:in\:long\:division\:format}:2381\overline{|5666}$

$\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space2$

$\mathrm{Divide}\:5666\:\mathrm{by}\:2381\:\mathrm{to\:get}\:2:381\overline{|5666}\space$

$\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space2$

$\mathrm{Multiply\:the\:quotient\:digit}\:\left(2\right)\:\mathrm{by\:the\:divisor}\:2381:2381\overline{|5666}$

$\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\underline{4762}$

$\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space2$

$\mathrm{Subtract}\:4762\:\mathrm{from}\:5666:2381\overline{|5666}\space$

$\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\underline{4762}$

$\mathrm{The\:solution\:for\:Long\:Division\:of}\:\frac{5666}{2381}\:\mathrm{is}\:2\:\mathrm{with\:remainder\:of}\:904$

.

cryptoaopsJan 25, 2021

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