123 + 359 = ??? = the original height above the ground
It is a confusing question but this is my interpretation
5+2430 = 2435
Yes Kit, guest has a valid point....
I will give a hint:
\(0.025\% = \frac{0.025}{100}\)
Multiply top and bottom by 1000 by moving the point 3 places in the direction to make the number bigger.
Whole numbers really do have a point, it is at the end and it is invisable.
Now that you have 2 whole numbers, top and bottom, simplify.
1.continuous
I have assumed that the answer will be the same where ever P is put. (P is on the incircle of course)
The easiest place to put P is on the midpoint of one of the sides.
Now all the distances are really easy to find.
I will leave that to you though.
U are def in my AoPS class
You didn’t give a hint. You just restated part of the instruction.
Yep, Melody was wrong.
Since 7x8= 56 and 7x9= 63 the answer would be 8 since 63 is 2 higher than 61 or if you do this 7x8=56 61-56= 5, so the bottom number is supposed to be equal to or less than, so if you go to do 61-63=
you can't do it.So that means the answer is definitely 8
Thx this helps a lot
Same thing as hihihi and KSW said... but more detailed (i think)
\(2n+5=15\:\:\)
\(\mathrm{Subtract\:}5\mathrm{\:from\:both\:sides}\)
\(2n+5-5=15-5\)
\(\mathrm{Simplify}\)
\(2n=10\)
\(\mathrm{Divide\:both\:sides\:by\:}2\)
\(\frac{2n}{2}=\frac{10}{2}\)
\(n=5\)
By integration by parts, $\int_0^{10} xg''(x) dx = 18$.
Thank you
If two-thirds of a number is 10, we can write it out as 2/3x=10.
Multiply both sides by 3 to get 2x=30.
Simplifying we get x=15.
Checking our work 15*2/3=10
Question 2: The roots of x^2 - 6x + 2 = 0 are x = 3 - 2*sqrt(2) and 3 + 2*sqrt(2), so (r - s)^2 = (4*sqrt(2))^2 = 32.
Vivek, I believe we have the same answer, but anyways, Guest could you specify where you think I got the problem wrong?
I forgot this but I remember the website I used to learn it.
Here it is: https://web.williams.edu/Mathematics/sjmiller/public_html/OSUClasses/487/ArithMeanGeoMean.pdf
It's a great notes sheet.
I'm getting 4//5 < t <= 5/2, so in interval notation the solution is \((4/5,5/2]\)
this is an aops prealgebra 2 problem (I'm taking the course rn and it was the first problem in week 1.) so I'll give @Choff a hint instead of the answer.
try writing 0.025% as a fraction. What do you get?
btw, @Melody is wrong...
To add on to @Guests's, the question is asking for what A-B is. so A-B=4-2=2
start by converting 12 1/2% (0.125) as a common fraction -> 1/8
2000*1/8=250
this was posted twice but here is the answer
61/7=8 5/7 so the answer is 8
5666/2381
how many 2381s are in 5666? 2
what is 5666/2381 as a mixed number? 2 904/2381
1-0.4=0.6
then it becomes the equation 0.6x=16
divide both sides by 0.6 to get $26.67
363 minutes actually...but 364 is also fine