Let N be the first number
So the first three numbers are ( N ) + (N + 6) +( N + 12)
The last three numbers are ( N + 6 ) , (N + 6)r + (N + 6)r^2
So
AP third number = GP second number
N + 12 = ( N + 6)r
(N + 12/(N +6) = r
And
AP first number = GP last number
N = (N + 6)r^2
N = ( N + 6) (N +12)^2 /(N + 6)^2
N = ( N + 12)^2 / (N + 6)
N (N + 6) = (N + 12)^2
N ^2 + 6N =N^2 + 24N + 144
-18N = 144
N = -8
r = (N + 12) / (N + 6) = ( 4/-2) = -2
The series is -8 , -2 , 4 , -8
The sum is -14
