A segment with endpoints at A(2,-2) and B(14,4) is extended through B to point C. If \(BC=\frac{1}{3}\cdot AB\), what are the coordinates for point C? Express your answer as an ordered pair.
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\(\Delta x_{AB}=14-2=12\\ \Delta y_{AB}=4-(-2)=6\)
\(x_C=x_B+\frac{1}{3}\ \Delta x_{AB}= 14+\frac{12}{3}=28\\ y_C=y_B+\frac{1}{3}\ \Delta y_{AB}=4+\frac{6}{3}=6\)
The coordinates for point C are C (28.6).
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