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this is if the digit is allowed, the other question is if the digits are not allowed

There is this same question before so here is the link

Why did you repeat your question?

The answer on your prior post is correct; this answer is not....

thank you guest!!

Thank you for 2 but for 1 you have to make the equation.

1 )    x= 2   (just by inspection)

2 )   Multiple ways to do this one

           re-arrange into vertex form:

                  (x+4)² -16 + 23

                   (x+4)² + 7                      vertex is   -4,7

This is soo easy so I am just going to give you a way to solve it (no answer).  652-192-256= Your answer.

The answer is 402 sdrawkcab (PS 402 is NOT the correct answer, so see what I meant by sdrawkcab)

first digit must be a 5     so the remaining 7 digits can be anything (0-9) but they all start with a 5

10⁷    = 10,000,000  phone numbers

w*f is the answer tho......?

thank you

Hi Guest!

z = a + bi

(a + bi)^2 = i/2

a^2 - b^2 - 2abi = i/2

2a^2 - 2b^2 - 4abi = i

2a^2 - 2b^2 = 0

a^2 = b^2 (Important)

4abi = i

ab = 1/4 (Important)

So |a| and |b| are the same number. 

And since ab = 1/4 (positive), they must be both negative or both positive. 

So a = 1/2 and b = 1/2 or a = -1/2 and b = -1/2. 

z = 1/2 + i/2

z = -1/2 - i/2

I hope this helped. :)))

=^._.^=

y = (x+8)^2 - 5   IS the vertex form of the parabola    vertex =  -8,-5

Hello Guest!

2*(n+1)!+6*n!=4*(n+1)!

6n! = 2(n+1)!

6n! = 2n! * (n+1)

3 = n + 1

2 = n

I hope this helped. :))

=^._.^=

Christ! Anyone that can decipher your bullshit infused slop could more easily figure out how to solve the problem without it.

thank you!!

No landscape architect would use that scale nor mix imperial with metric units. Doing so only leads to errors and contractor confusion.  typically, a landscape architect would use an architectural or engineering scale such as 3/4" : 1'-0" or 1" : 10'.   Some use 1" = 10' but how can that be?  The perimeter length isn't of much concern in the construction documents.  But, calculation of area is needed for determining quantities for earthwork, stone or concrete base material and the pavers and used for estimating or bidding purposes.  Good luck with your comps!

As follows:

"find the values of A,B,C if (x-1),(x+2) and (x-2) are factor of 2Ax^4-Bx^3-Cx-16"

Use the button shown below

And do you really want the antilog of 10^-2.25, or do you mean the log of it? 

If there's a typo, and that 30 should be 31, then 4, 9, 25 would work.

12121 , 12123 , 12321 , 12323 , 12343 , 12345 , 32121 , 32123 , 32321 , 32323 , 32343 , 32345 , 34321 , 34323 , 34343 , 34345 , 34543 , 34545 , 54321 , 54323 , 54343 , 54345 , 54543 , 54545 , Total =24 such numbers

Let  the  legs of the isosceles  right triangle = 1

Then  the   purple  segmemt on the base = sqrt (2)

The  area of the right triangle =  1/2 (1)^2   = 1/2

And  1/2 =   (1/2) base (height

base * height  =  1

sqrt (2)  height   =1

height =1/sqrt (2)

So the  height  of this triangle  will    be 1/ sqrt (2)

And the  perpendicular distance  from  the point  where the  purple segment meets the  green line at the top left  to the base = the height of the triangle =  1/sqrt (2)

So   

Let A  be  the  angle  unshaded  part  of   the 45°  base angle

sin A  =   1/sqrt (2)  / sqrt (2)  = 1/2

A = 30°

So....the shaded angle = 45  - 30  = 15°

A is the start of the segment, then B then C

FROM A (2,-2)

Consider A to B    

x displacement  is  -14-2= -16        y displacement  is   4 - - 2 = 6

A to C is 4 times as far so

x displacement  is   -16*4=-64        y displacement  is    6*4= 24

But you are starting at A so the point C will be

C(2 + - 64, -2 +24)  =    C(-62, 22)