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Here is my solution:

Square area + tri area = total

(9*9)             + 1/2 (9)(9) = total area =............ cm²                         (triangle area = 1/2 b * h   = 1/2 *9*9)

66² = 4356

=

2 x 12^3     +

6 x  12^2    +

3 x 12^1

0  x 12^0

2630₁₂  = 4356₁₀

umm no but here is their example they give me

"Subsidy" means financial aid by either the University, one form or another of some government, a foundation......etc. You have to state the amount of subsidy and its terms. As a result, the loan payments may be  quite a bit less than without subsidy.

y=100(0.02)+x(0.005)100+x       and you want y=.77

.77 = 100(.02) + x(.005)100  + x        and solve for x   (if that is the correct equation in your Q )

PLZ Help.

-4y=x
5x-10y=-50         substitute x = -4 y   into this equation

5 (-4y)  - 10y = 50

-30y = 50

y = - 5/3                    now use this value of y to compute x      -4 (5/3) = x   =..........

DO you have one of these that is completed correctly?   I do not know what they want.......

As follows (I think!):

Since   x   = y

Then

-3x  - x =  4

-4x   = 4

x  = 4  /  -4     =  -1

So   y  = the same thing   

No number lines shown....

It's solved now. :))

=^._.^=

5x = 4x+9

x = 9

I hope this helped. :)))

=^._.^=

8x = 10x-4

4 = 2x

x = 2

I hope this helped. :)))

=^._.^=

Can you explain how you got that?

Plug   x  into one of the equations

y = 5(9)  = 45

tan  BDC    =   sqrt 3    /  3    =    1 /sqrt 3)

So  BDC   =  30°

Then CE  is opposite a 30°  angle in right triangle DEC

So...it has  half the  length  of  the hypotenuse  DC   = (1/2) 3 =    3/2

Whats Y?

Translate the following phrase into an algebraic expression using the variable wi. Do not simplify.

the perimeter of a rectangle if the width is w centimeters and the length is 2cm less than twice the width.

Hello Guest!

\(P_{rect}=2(wi+ l)\\ l=2\cdot wi-2cm\\ P_{rect}=2(wi+2\cdot wi-2cm)\)

\(P_{rect}=2(3wi-2cm)\)

\(w\ is\ a\ number \\ \color{BrickRed}if\ wi=w\ cm\\ then\\ P_{rect}=2\cdot (3\cdot w\ cm-2\ cm)=6w\ cm-4\ cm\\ \color{BrickRed}P_{rect}=6w\ cm-4\ cm \)

  !

Just set  the y's equal

5x  = 4x + 9

5x - 4x  = 9

x =  9

The  hypotenuse    =    sqrt  [ (99^2  + 30^2  ]   /101  =   101/ 101 =   1

The  other altitude will  be  drawn to  this hypotenuse and  its length =  product  of the  legs/ hypotenuse  length  =

So    (20 / 101  *  99 /101)  / 1  = 1980 / 10201    ≈     .194  = x

\(\displaystyle \frac{f(x)}{x-19}=q(x)+\frac{91}{x-19},\\ \text{so} \\ f(x)=q(x)(x-19)+91, \\ f(19) = 91.\)

Similarly,

\(\displaystyle f(x)=r(x)(x-91)+ 19, \\ f(91) = 19.\)

\(\displaystyle \frac{f(x)}{(x-19)(x-91)}=s(x)+\frac{ax+b}{(x-19)(x-91)}, \\ f(x)=s(x)(x-19)(x-91)+ax+b,\\ f(19)=91=19a+b, \\f(91)=19=91a+b.\)

Solving simultaneously,

\(\displaystyle a=-1, \\b=110.\)

so the remainder is 110 - x.