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Common ratio  =   2/-5  =  -2/5

Sum  =     first term  / ( 1 - common ratio ) =

-5 / ( 1 - - 2/5)    =  

-5/ ( 7/5)   =

(-5) 5/7 =   

-25/7

The answer was 73

The angles around vertex $O$ sum to $360^{\circ}$, so we have \[ \angle AOB+\angle BOC+\angle AOC = 360^{\circ}. \]In particular, \begin{align*} \angle BOC &= 360^{\circ} - \angle AOB - \angle AOC \\ &= 360^{\circ} - 99^{\circ} - 133^{\circ} \\ &= \boxed{128^{\circ}}. \end{align*}

1st. Why a math test? you are supposed to answer it with your own knowledge

2nd. I think the answer is 0.081

help someone pls with the answer

That is inncorrect a pentagon has 5 verticies, that means a pentagon has 5 angles, a shape with 6 angles would be a hexagon.

[WCXYFZ] = 1.058475491 square units

Nice job both of you!

btw, I figured out the answer.

I use Aops too.

Is this a Math Masters problem?

Do the Alegebera, 

1. 3x=2x+12, we need to bring x terms to 1 side and numberes on the other, we now have 3x-2x=12, 
2. now you need to subtract 3x-2x=x, you now have x=12, 12 is the only value that satifies this equation.

 

Do the Alegebera, 

1. 3x=2x+12, we need to bring x terms to 1 side and numberes on the other, we now have 3x-2x=12, 
2. now you need to subtract 3x-2x=x, you now have x=12, 12 is the only value that satifies this equation.

Got it. Thank you so much guys! 

NOW what do you see IhaveOBJD ?

 You have to be careful with what you see as diagrams are often 'not to scale'  or misrepresented....

suubtracting 2x from both sides, you get:

x = 12

hope this helped! :)

X must equal twelve for that statement to be true.

this site also helps  https://journeywithdp.blogspot.com

BTW....here's a good  website  that explains some  of this  : https://journeywithdp.blogspot.com/2018/09/distributing-balls-into-boxes.html

wait sorry i understand

not helpfull

I'm  assuming  that we have no restrictions   ( some boxes can  be empty)

1.   k  distinct balls  into  n  distinct boxes =   n^k   = 4^4 =  256  ways

2. k indentical balls into n identical boxes   ....this one  is tough....it involves partitions.....as I'm going to  have to leave in a minute....I'll see if I can give you an answer later

3.   k identical balls into n distinct boxes  =  C (k +n - 1 , n-1) = C( 4 + 4  -1, 4 -1)  = C(7,4)   = 35 ways

C (7,4)   is the number of ways to  choose  4 things from 7  ....in case you are  not familiar with this  notation

Tesla would agree with both, Jugoslav and Alan because their answers are correct!!!