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Notice that $x_3=1+1=2=(-1)\pmod{3}$. And $x_4=1+1=2=(-1)\pmod{3}$ again. So $x_5=1-1=0$. Then, $x_6=-1\pmod{3}$. And $x_7=1\pmod{3}$. And $x_8=0\pmod{3}$. Then $x_9=1\pmod{3}$. Then, $x_{10}=1\pmod{3}$. So it cycles $\pmod{8}$ with $1,1-1,-1,0,-1,1,0$. There are $\lfloor \frac{2018}{8}\rfloor = 252$ cycles, with 2 more left over. Since none of the two left over have $0$'s, the answer is $2*252=\boxed{504}$.

I got the answer alr.
No need to do it.

Thanks!

Yes I agree with IhaveOBJD, there's no possible way for DGF to be 30, 30 = AB or BC or CD or AD, not DGF area.

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very nice, vockey!

the sum of the interior angles of a pentagon: (5-2)*180 = 540

adding up all the degrees to make an equation, you get:

7x+4+5x+4+4x+9+9x-6+4x+1 = 540

simplifying that (by combining the like terms and adding the constants), you get:

29x+12 = 540

29x = 528

x = 528/29 = 18 6/29

hope this helped! please correct me if i am wrong:)

I disagree as AB is 30cm and not DG

Even if DG was 30, that's not the way to find the area of a triangle!

So DGF can't be 30 square.

So we know in a pentagon there are in total 540 degrees.
Then, 7x+4+5x+4+4x+9+9x-6+4x+1 = 540 = 29x + 12

540-12 =  528

528/29 = x

Let me know if you have any questions about the way I solved.

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Pls do!!!

tan∠EFA = 30 / 18

DG = tan∠EFA  * DF

[DGF] = 30 cm²

or

18 / 30 = 6 / DG

DG = 10

[DGF] = 1/2(10 * 6)

The answer is 45, I can't put a explanation but if you want one reply.

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However, if there is more information, please tell us so we can actually help you!

If it's a heptagon, then the total sum of the angles is 900 degrees.

The sum of these numbers given is 724.

If we take the next two angles as equal, then that would mean that the 6th angle is 88 degrees. 

(Idk whether that's correct since I didn't know the angle of the 7th angle. Please tell me if it's wrong or right)

Hope it helps!!! :)

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ohhhh okay

Wait, oops sorry its a heptagon. It has seven sides

It is a pentagon

😳😳😳😶😶😶🤔🤔🤩🤩

I also think that you should elaborate on the question. Someone else asked a similar question (I'm guessing it was this Guest User) but if you use the logic that mac0roni used, you will get -4. -_-

So, if you asked that question, please elaborate on it.

log _4^x  (2^a)  =   3     using the  change of  base rule  we  have

log 2^a

______  =   3

log 4^x

a log  2

________  =  3

x log 4

a log 2

________   =    3

x log 2^2

a log 2

________    =    3

2x log 2

a

__  =   3

2x

a =  3*2x

a  = 6x

Could you pls elaborate the question. I don't understand which shape it is. If it's a hexagon, then that would mean that the sixth angle is -4 degrees.

The remainder is 4.

i am not sure if you mean that the three angles are in a quadrilateral, but if so:

360 - (79+55+110) = 360 - 244 = 116 degrees

hope this helped! please correct me if i am wrong, or if i misunderstood the question:)

The  length  of  one side =   2sqrt (3)  +  8     =   sqrt (12) + 8

So....the  area   =    (1/2)  (sqrt (12) + 8)^2  sin (60°)   =

(1/2)  (sqrt (3) / 2 )  [  12 + 16sqrt (12) + 64)  =

[sqrt (3) /4]  [ 76 + 16sqrt (12) ]  =

[sqrt (3)/ 4 ] [ 76  + 32 sqrt (3) ]  =

[76 sqrt (3)   +  32 * 3  ]  /  4   =

19sqrt (3)  +  24  ≈    56.91  units^2

Awww, thank you. :3

=^._.^=