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Wait what was the answer. I'm curious

i get it now, thank you so much!

356  to  Base  8

356  / 8   =  44  +  R 4

44/8  =       5  +  R4

5/ 8    =     0  + R5

5(8)^2  + 4(8)  + 4  =

5 (64)  + 32  + 4  =

320 + 32  + 4   =

356   !!!

So   544₈

As follows:

yes, Vockey, i think that is right! :)

Real and Rational

So that would mean 356 in base 10 to base 8 is

356 / 8 = 44 + remainder 4

44 / 8 = 5 + remainder 4

4 / 8 = 0 + remainder 4

So 356 converted is 444?

@cphil

BE = BC = 8           BD = EF = 2              BG = 5            CH = 4

∠CBE = cos^-1(BG / BE)

∠ABC ≅ ∠ACB = 1/2(180 - ∠CBE)

AB = BH / cos∠ABC  

Converting out of  base 10

Using  the base that Alan found    62  base 10  to Base 4

62 / 4  =    15   +  Remainder  2

15  / 4   =   3   +  Remainder  3

3  / 4  =   0  +  Remainder    3               

We stop  when the division  produces a whole number  of  0

Read  the remainders  "backwards"  from  bottom to top  = 

332₄  

Thanks a lot!

Like so

545787*854376=466307313912

12+15=27

27-25=2 people but we want to know the percent

2/25=0.08=8%

just plug all of them in, lol. 

(-8)(4)(2)+(-32)=-96 

30/2=15 miles in 1 min

number of degrees in a hexagon = 720deg

720-119-129-104-139-95=134 degrees

interior angles of a pentagon = 540deg

so we set up the equation (7x+4)+(5x+4)+(4x+9)+(9x-6)+(4x+1)=540

combine like terms and simplify and divide both sides by 29 to get 528/29

ok since we know that x=y we only need to solve for x and then y would be the same thing

so we basically just solve the equation -3x-y=4 (divide both sides by -4 to get x=-1) and y would be the same thing as x. 

FOR X: write 5x in terms of y, add -4x to both sides to get x=9

FOR Y: substitute 9 -> y=5x to get y=45

@catmg what about y: 

FOR X: write 8x in terms of y, add -10x to both sides, and divide both sides by -2 to get x=2

FOR Y: substitute 2 -> y=8x, simplify to get y=16

I agree with jugoslav:

Notice that $a_n=n^2$. By the sum of squares formula, the answer is $\frac{100(100+1)(2*100+1)}{6}=\boxed{338350}$.

Let $AC\to P = x$. Call $P\perp AC=K$. Call $P\perp AB = K_1$. Call $P\perp BC=K_2$. We know that $AK=AK_1=10-2x$. We know that $BK_1=BK_2=24-x$. Therefore, $AK_1+BK_1=26\implies 10-2x+24-x=26\implies 34-3x=26\implies x=\frac{8}{3}$. And we want $2x=\boxed{\frac{16}{3}}$. 

You're right, thank you