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$18(-8c+16) - 13(6+3c)$

$-144c + 288 - (78 - 39c)$

$\boxed{-105c + 210}$

-12 + 73.26 - 65.50 = $ -4.24

$(\frac{7}{9})^2 = \frac{7}{9} \cdot \frac{7}{9} = \boxed{\frac{49}{81}}$

$\tan(30) = \frac{\sin{30}}{\cos{30}} = \frac{1}{2} \cdot \frac{2}{\sqrt{3}} = \boxed{\frac{\sqrt{3}}{3}}$

$1 + \frac{5}{6} = \boxed{1 \frac{5}{6} \quad \text{or} \quad \frac{11}{6}}$

Add 3 zeros on the end. Here are a few examples:

23 * 1000 = 23,000

4 * 1000 = 4,000

29438 * 1000 = 29,348,000

This tutorial should help you:

If the coordinates of the original point are (x, y), the coordinates after rotating 90 degrees clockwise are (y, -x).

Let the length of FJ be x. Because of the triangle inequality, the sum of two sides must be greater than the third.

10 + 26 > x

10 + x > 26

26 + x > 10

Simplifying, we get the following:

36 > x

x > 16

x > -16

The greatest integer length of x is 35.

Let the length be L and the width be W. Then, $\sqrt{L^2 + W^2} = 40$. No other information is given, so this is the best I can do.

Let the number you are trying to convert be x%.

$x\% = \frac{x}{100}$

Hope this helped.

This is binomial expansion.

$(x+2)^6 = {6 \choose 0}x^62^0 + {6 \choose 1}x^52^1 + {6 \choose 2}x^42^2 + {6 \choose 4}x^22^4 + {6 \choose 5}x^12^5 + {6 \choose 6}x^02^6$

Hi. How can I write "/" in this app?     

You want to insert a virgule while using the calculator? 

You can use the / key on your physical keyboard to create a fraction. 

Or you can use the ÷ key on the virtual keypad and it will do the same thing.  

_.

Miko and Freya saved the same amount of money, so let this amount be x.

5(x - 32) = x + 32

5x - 160 = x +32

4x = 192

x = 48

Freya had x + 32 = 80 dollars in the end.

Show me what you have done?

I don't know what you are talking about....

how do you substitute?

Find the sum of the squares of the solutions to $2x^2+4x-1=0$.

$\begin{array}{|rcll|} \hline 2x^2+4x-1 &=& 0 \quad | \quad :2 \\ x^2+2x-\dfrac{1}{2} &=& 0 \\ \hline \end{array}$

By Vieta:

$2 = -(x_1+x_2) \\ -\dfrac{1}{2} = x_1*x_2$

$\begin{array}{|rcll|} \hline x_1^2+x_2^2 &=& (x_1+x_2)^2 - 2x_1*x_2 \\ x_1^2+x_2^2 &=& (-2)^2 - 2*\left(-\dfrac{1}{2}\right) \\ x_1^2+x_2^2 &=& 4 + 1 \\ \mathbf{x_1^2+x_2^2} &=& \mathbf{5} \\ \hline \end{array}$

Solve for $z$ in the following equation: $2-iz = 1 + 3iz$.

$\begin{array}{|rcll|} \hline 2-iz &=& 1 + 3iz \\ 2-1-iz-3iz &=& 0 \\ 1-4iz &=& 0 \quad | \quad \times i\\ 1*i-4i^2z &=& 0 \\ i-4i^2z &=& 0 \quad | \quad \mathbf{i^2 = -1} \\ i-4(-1)z &=& 0 \\ i+4z &=& 0 \\ 4z &=& -i \\ \mathbf{z} &=& \mathbf{-\dfrac{i}{4}} \\ \hline \end{array}$

differentiate y with respect to x and substitute in x=e.

If you still can't do it explain which bit is giving you trouble.

xy + y ^ 3 = 4x - 3

$x\frac{dy}{dx}+1\cdot y+3y^2\frac{dy}{dx}=4\\~\\ (x+3y^2) \frac{dy}{dx}+y=4\\~\\ \frac{dy}{dx}=\frac{4-y} {x+3y^2} \\~\\$

where  $x\ne -3y^2$

$\frac{\sqrt{2} \cdot \sqrt{3} \cdot \sqrt{4}}{\sqrt{5} \cdot \sqrt{7} \cdot \sqrt{9}}$

$\frac{2 \sqrt{6}}{3 \sqrt{35}} \cdot \frac{\sqrt{35}}{\sqrt{35}} = \frac{2\sqrt{210}}{105}$

This is all for now, I'm going to bed.

$\frac{1}{\frac{\sqrt{2}+2}{\sqrt{2}+1}} = \frac{\sqrt{2}+1}{\sqrt{2}+2} \cdot \frac{\sqrt{2}-2}{\sqrt{2}-2}$

$\frac{2 + \sqrt{2} - 2\sqrt{2} - 2}{-2}$

$\boxed{-\sqrt{2}/2}$