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\(\frac{-7}{3w} = 0.35\)

\(-7 = (3w)(0.35)\)

\(w = \frac{-7}{1.05} = \boxed{\frac{20}{3}}\)

(sniped)

-7 = 1.05w

-20/3 = w

Range of values will be BIGGEST when x = 0        1/2

and will tend toward  0 as x gets larger and larger    (but never actually becomes zero)                  (0, 1/2]

This is arithmetic growth, since this is a linear addition of 50 students.

Your question was automatically rejected all four  (or 5) times that you posted.

I am just guessing, but I think this is most likely because you used the word 'death'.  

Whatever Jenny multiplies by  sqrt2 needs to be a perfect square (or 2)

    sqrt 2   * sqrt 2    =  2

     sqrt2   * sqrt 8    =  sqrt 16 =  4

     sqrt 2 * sqrt 32 = sqrt 64 = 8  

    Red numbers are her possible fav's        

b.    let 's   see       sqrt 2 / sqrt 2 = 1

              sqrt8 / sqrt 2 = 2

              sqrt 32/sqrt 2 = 4                    Yes she gets an integer

"with better methods than this one" Is there any better math than right? At school?

  !

Volume of cylinder = pi r^2 h         make sure units are in the same dimension  ....covert yards to feet

2500 yd³ *  27 ft³/yd³  = 3.14 * 36 * r^2

r = 24.44 ft     = 8.15 yd

There is no Question...........

e = k v^2       k = proportionality 'k'onstant

72 = k (24^2)

k =  72 / (24^2) = 0.125

e = .125 v^2

e = .125 * 27² = 91.125 j

Performing some synthetic division

2  [  2      -9          13        k    ]  

                4         -10       6

     ______________________

      2      -5           3         k +  6

So

k + 6   =  0

k  =   -6

So.....

2   [   2         -9       13       -   6     ]

                    4        -10          6

      ___________________________

        2         -5        3            0

The remaining polynomial is

2x^2  - 5x   +  3   =   0

(2x  - 3) (x  - 1)   =    0

Set each factor to 0  and solve  for    x    and we  get  that   the other two roots  are

x =  3/2     and   x   =  1

We  have

1 , 1/2, 1/3, 1/4 ,  etc

a)   the  common difference  is         1/ (n + 1)  -   1/n  =   (n - (n +1)) /  (n* (n+1))  = 

-1 / (n(n+1))

b)  a_{n+ 1} =    1/n -  1 / (n(n+1)) =    (n + 1  - 1)/ (n (n + 1))  =      n / (n (n +1)) =   1/ (n +1)  

Just  multiply  numerators and  denominators

So

3/4  x   4/19  x  6/8

One  of the  nice  things about  multiplying fractions  is that  we  can rearrrange numerators and denominators....also we can  reduce, where possible...so we can do the  following :

4/4  x  3/19 x 3/4   =

1   x    3/19 x 3/4   =        (3 * 3)  / (19 * 4)   =    9 / 76       and that's it  !!!!

Perimeter  =  2  ( W + L)

282 =  2  (59 + L)     divide both sides  by  2

141  = 59 +  L          subtract  59  from both sides

82 m =  L

First, to find out what k is, just use the remainder theorem: if x=2 is a root, then when you evaluate the polynomial at 2 you should get zero. Plugging 2 in for x:

\(2\cdot2^3 - 9\cdot2^2+13\cdot2+k = 0\\6+k=0\\k=-6\)

Knowing that, just use polynomial division to divide this into a quadratic:

\(\hspace{2.35cm}2x^2 - 5x + 3 \\x-2|\overline{2x^3-9x^2+13x-6}\\ \hspace{1.15cm}2x^3 - 4x^2\\ \hspace{2cm} \overline{-5x^2+13x}\\ \hspace{1.8cm} -5x^2 + 10x\\ \hspace{3.75cm} \overline{3x-6}\\ \hspace{3.75cm}3x-6 \\ \hspace{4.75cm} \overline{0}\)

Then, factor the quadratic:

\(2x^2-5x+3 = (2x-3)(x-1)\)

Therefore, the two other roots are \(\boxed{\frac{3}{2}, 1}\)

some one i need help with this 

There have been at least two other (with better methods than this one) answers to this question posted within the last week.

Look for them.

Find all solutions to:

ab + 2a + 2b = −16

ac + 2a + 2c = 26

bc + 2b + 2c = −14

Hello juananother!

\( ab + 2a + 2b = −16\\ a(b+2)+2b=-16\\ a= -\dfrac{16+2b}{b+2}\\ \ \\ ac + 2a + 2c = 26\\ a(c+2)+2c=26\\ a= \dfrac{26-2c}{c+2} \)

\( -\dfrac{16+2b}{b+2}=\dfrac{26-2{ \color{BrickRed} c}}{{ \color{BrickRed} c}+2} \)

\(bc + 2b + 2c = −14\\ \color{BrickRed} c=( -\dfrac{14+2b}{b+2}) \)

\(-\dfrac{16+2b}{b+2}= \dfrac{26-2{ \color{BrickRed} (-\dfrac{14+2b)}{b+2}}}{{ \color{BrickRed} (-\dfrac{14+2b}{b+2})}+2}\)

\(b= -\dfrac{8}{3}\)

\(c= -\dfrac{14+2\cdot (-\dfrac{8}{3})}{-\dfrac{8}{3}+2}\)

\(c=-13\)

\(a= \dfrac{26-2(-13)}{(-13)+2} \)

\(a=-\dfrac{52}{11}\)

  !

Hi Textot,

This girl is using a few different identities and she is getting you and others here to do all her homework for her.

Please do not give her full answers like this.   Part answers and good hints are always better.

You can encourage her to interact with you.

You can make up a similar question if you like and show her how to do that one.

There are many options, just please do not give her answers that she can just copy.

[PCQ] instead of [PSQ] 

In triangle ABC, through the midpoint of AC is drawn PQ I| AB. The altitude CD = 6 cm. If PQ is 8 less than AB, find PQ and the area of PCQ.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

"If PQ is 8 less than AB..." then PQ = 8, and AB = 16

[PSQ] = 1/2(PQ * CD/2) = 12 cm²

A rectangular tennis court is 78 ft long and 36 ft wide and is surrounded by a uniform pathway. If the total area of the tennis court along with the pathway measures 3280 ft, find the width of the pathway.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Pathway width  =>  w

(78 * 36) + 4w² + 2(36w) + 2(78w) = 3280

w = 2 ft

https://web2.0calc.com/questions/a-few <- heres the answer 

Your question is not correct!!!

https://web2.0calc.com/questions/need-help-please-asap_36

Using some  logic

20  - 30 cent items  =             $6

6 -     2 dollar  items  =          $12

4 -     3 dollar  items  =         $12

__                                         ____

30           items                       $30