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1.1^2x3.14x4/1.5=15.1976/1.5 ≈ $\boxed{10}$

Suppose oil is drained at arate of 1.5 per minute.       1.5 WHAT per minute?   Gallons?   ft³ ?

Asuming  ft^3 per minute drain rate

volume = pi r^2 h =   pi ( 1.1)^2 (4) = 4.84 pi   ft³

4.84 pi   ft³  / 1.5 ft³ /min   = ~~ 10 minutes       as SW calc'd !   ( an explanation would have been good)

(I'm not very good at functions... but I think this is correct)

h(t)=44t-16t^2

t=44/32=11/8

h(t)=44(11/8)-16(11/8)^2=121/2-121/4=$\boxed{\frac{121}4}$

The answer is 552

$\boxed{third \ one}$ beacuse 5/4x4x1=5

for this, we would have to swap between odd and even numbers for the arrangement, so

4x3x3x2x2+4x3x3x2x2+4x3x3x2x2+4x3x3x2+4x3x3+4x3=$\boxed{552}$

3^2+3*2=15

a+b=$\boxed{5}$

2(x+80+70)=360=2x+300

x=$\boxed{30}$

The little angle between  70 and 80 is the same as x     and they all sum to 180

70+ 80 + x = 180

x = 30

By power of point, we have 10$\cdot$27=9(9+x)=270=81+9x

9x=189

x=$\boxed{21}$

1. y=5$\sqrt2$

x=10

2. y=4$\sqrt6$

x=8$\sqrt6$

3.x=5$\sqrt3$

4. 12$\sqrt3$

3 since y=3x-2

$\boxed{B}$ because 70+110=180, which is true.

2x2 1/4=9/2

(9/2)/(1/2)=9/2x2/1=$\boxed{9}$

Lets call BD x. using pythagorean theorum, we have:

16+x^2+225+x^2=361

241+2x^2=361

x^2=60

x=$\boxed{2\sqrt{15}}$

5^8+5^7+5^6+5^5+5^4+5^3+5^2+5=$\boxed{488280}$

A triangle with two equal side lengths is an ISOSCELES TRIANGLE .

Y=3X-2      I believe gradient is slope , m          m = 3

Isosceles trapezoid    the two angles shown are  equal

4x + 10 = 62

4x = 52

x = 13

P = volume of P

Q = 1.5 P

R =  1.5 ( 1.5P)    =  2.25 P

P/R = 1/2.25 =   4/9

15% discount means H pays   100% - 15% = 85% of the original price

.85  *  $ 35 = $ ...........

Maybe your Q is missing something?

This will work     -1 -2   = -3   ?

Lateral Surface Area:
(20 x 10) + (16 x 10) + (12 x 10)

= 200 + 160 + 120

= 360 + 120

= 480 cm²

There is one solution.
There are infinitely many solutions.
The solution is (0, 4)