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Slope of first line     y = x-3         m = slope = 1

Slope of second line   ay = ax - 3a     slope is also 1   (no matter what value of nonzero a is chosen)

   the lines are parallel ....no solutions

(180-136)/2=22

10x-8=22

10x=30

x=$\boxed3$

105=3x7x5

3+x=4(mod 27)

5+x=9(mod125)

7+x=25(mod343)

x=1(mod27)

x=4(mod125)

x=18(mod343)

27k+1=x

3(9k)+1=x

x=1(mod3)

for the same reasons:

x=4(mod5)

x=4(mod7)

x=4(mod 35)

possible sollutions lower than 105:

4, 39, 74.

the only one that has a remainder 1 when divided by 3 is $\boxed{4}$

SP = UP = 9

TR = UR = PR - UR = 12 - 9

TR = 3

It is clear you have rebirthed yourself Doggo,  or is that  xXxTenTacion  ?

It appears at least some of your bad habits are continuing.

When you vote people down for no good reason, you are not invisible to all.  I can see what you get up to.

I strongly suggest that you behave better in this regard.

I can see that your new persona is answering some questions, at a glance they appear to be proper answers.

That is commendable.

I strongly suggest that you continue your good behaviours and lose your bad ones.

Why would you want to make a bad impression (again) ?

It is highly likely that I do not understand the question properly.

BUT

If n=1

then x=1

\(1=1^\frac{a*1+b}{c}\\ 1=1^\frac{a+b}{c}\\ \)

If a=1, b=2 and c=3   (they are all relatively prime.)

 Then a+b+c=6

You are not going to get any positive numbers smaller than those.

I tried that but it was wrong. Please help!

Wow, thanks!

Could you explain what you mean by low digit, high digit and groups of three?

Almost.

You certainly only have one sock of the right colour in the mix so the 1 is correct.

But it would be put over the total number of REMAINING socks.

You took one out already so there are not 20 socks to choose from.  

When a quadrilateral is inscribed in a circle, the sum of the opposite angles is 180 degrees.

∠DEF + ∠FGD = 180

4x + 27 + 16x - 21 = 180

x = 8.7

∠DEF = 4x + 27 = 4*8.7 + 27 = 61.8º

∠FGD = 16x - 21 = 16*8.7 - 21 = 118.2º

2x - 1 = x + 8

x = 9

3x - 3 = 3*9 - 3

BC = 24

1. DC is tangent to circle O at C. If ∠ABC = 59 degrees, ∠BAC = 60 degrees, and ∠BCA = 61 degrees, then what is the measure of ∠ACD?

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Important: The measure of angle ACD is equal to the measure of angle opposite side AC.

∠ACD = 59º

The angle will still be the same, no matter what size, so z is still 34 degrees.

Notice that 9 and 5 are the only measurements that stay. 

To find the proportion (idk if thats the right word) between the two triangles, we make a fraction, \(\frac{5}{9}\). We do this so that we can figure out the lengths of each side by multiplying and/or dividing.

To find y, we multiply 18 by \(\frac{5}{9}\), getting 10, so y is 10.

To find x, we have to DIVIDE 8 by \(\frac{5}{9}\), since unlike y, x is on the left triangle.

8 divided by \(\frac{5}{9}\)is 14.4, so x is 14.4.

So the final answer is:

x = 14.4

y = 10

z = 34 degrees

Correct me if I'm wrong! 

We can solve this by subtracting the area of the driveway from the entire rectangle

The area of a rectangle is \(lw\), so multiplying 14 by 32, we get 448

Now we need to find the area of the driveway. We can split up the driveway into 2 rectangles, one big rectangle at the left and a tiny rectangle in the upper right.

To find the area of the big rectangle in the driveway, we multiply 10 by 20, getting 200.

To find the area of the tiny rectangle in the driveway, we subtract 20 from 26 to find the length, which is 6.

Now we need to find the width of the tiny rectangle. We can do this by subtracting 7 from 10, getting 3.

Multiplying 6 by 3, we get 18, so the area of the tiny rectangle is 18.

Adding 200 to 18, we get 218, so the area of the driveway is 218 ft squared.

Now we need to subtract 218 from 448.

448-218=230

So the answer is 230 ft squared

Correct me if I'm wrong! 

Correct :)

Sparkling Water 2, it's actually 3 but your method is correct. Just a simple mistake, 15/5 = 3, not 5.

I agree with Swag :)

Just find the radius of the circle using the Pythagorean theorem, then use the formula pi*r^2 to find the area of the circle, and finally subtract the area of the rectangle from the circle. 

https://web2.0calc.com/questions/i-need-some-help-thank-you

Same question

Search up your question online before asking for help on here, it probably has already been solved before

https://brainly.com/question/4806554

Same question

To find the diameter of the circle, we need to use the pythagorean theorem and use it on one of the triangles in the rectangle.

Pythagorean theorem: \(a^2+b^2=c^2\)

Lets replace a with 21 and b with 20 to get the equation \(21^2+20^2=c^2\)

Simplifying the left side gives us \(841=c^2\)

which means that \(c = \sqrt{841}\) which is exactly \(29\)

Now that we know the diameter of the circle, we can find the area.

The formula for the area of a circle is \(𝜋r^2\), r being the radius.

We can find the radius by dividing 29 by 2, 14.5
Using the formula, we get A ≈ 660.52

So the area of the circle is about 660.52

To find the area of the rectangle inside the circle, we multiply the length by the width.

21*20=420

Now we subtract 420 from 660.52

660.52-420 = 240.52

x = 3 

Cos (M) = $\frac{24^{2}+51^{2}-45^{2}}{2\cdot 24\cdot 51}=\frac{1152}{2448}$

M = cos$^{-1}$($\frac{1152}{2448}$) ≈ 61.9 ≈ $\boxed{62}$

They must be equal, so

7x+8=2x+23

5x=15

x=$\boxed{5}$

Absolute change: 729-351=$\boxed{378}$

Relative change: $\frac{729-351}{351}=\boxed{\frac{14}{13}}$