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If a pyramid has 14 edges, how many vertices does it have?  

I'm not sure what you mean by "edges" ... Think of a pyramid with a triangular base and three sides.  It has the three vertices on the base and the three vertices going up to the point at the top.  That's six total.  Apply the same reasoning to pyramids with a different number of sides.  

a) 180 = 5x - 2 + 62 

     120 = 5x

         x = 24

b) 5x - 2 + 7y + 6 = 180

     5(24) + 7y + 4 = 180

              124 + 7y = 180

                         7y = 56

                           y = 8

c) b is parallel to c because a is parralel to c and b. 

pisagor's rule: \(L=\sqrt{5^2+12^2}= 13\)

Hey there!

Assuming that the bottom is flat and it comes to one point at the top, the pyramid will have 15 vertices!

Hope this helped :)

From x + 3y = -5, y = -x/3 - 5, so the slope of the line is -1/3. The slope of the new line is also -1/3, so y = -x/3 + B.  Pugging in x = 2 and y = -7, we get -7 = -2/3 + B, so B = -19/3.

Then the line is y = -x/3 - 19/3.  Then 3y = -x - 19, so 3y + x = -19.  We want the right-hand side to be 3, so we mutiply both sides by -3/19: -9/19*y - 3/19*x = 3.  Therefore, A + B = -9/19 - 3/19 = -12/19.

(OP speaking here) Noooo!!! I thought I was right, but I was wrong. I don't even know what the answer is anymore :(

12 + 9 + 9 + 5 = 35

7/2 = 3.5

35 * 3.5 = 122.5

Perimeter of figure a is 122.5 units

That is exactly what I got! I totally agree!

The probability is 0.75.

Thank you, but the corrrect answer is 10.

Can you try this problem?

What is the smallest integer n, greater than 1, such that n^-1 is defined?

The answer is 48,086.

u = (p^2 + q^2)/(p + q).

6^2 + 3^2 = x^2

36 + 9 = x^2

45 = x^2

x = sqrt45

x = 3sqrt5

By Stewart's Theorem, BD = 6.

2(2x - 1) = 3x + 5

4x - 2 = 3x + 5

x = 7

I can't see any picture.

I found this problem on line at https://brainly.com/question/4528670  

Each triangle is a right triangle with a base 9 inches and a height 16 inches.  

That would make the area of one triangle 72 inches².   

Your answer is C. 72 square inches

_.

Since the centroid divides the median of a triangle in 2:1 ratio,

\({3x+5 \over 2x-1} = {2\over 1}\)

⇒3x + 5 = 4x - 2

⇒x         = 7

x^(logx) = 10

Hmmm, I'm kinda weak on logs, but isn't 1 the log of 10.  In base 10, of course. 

That would make x = 10 in this problem.  Don't take that to the bank, I'm not sure. 

Hey there!

There would be method there but i started trial and error and got it on my third go :)

1+2+3+4+5=15

1*2*3*4*5=120

Hope this helped :)

They're 1, 2, 3, 4, 5  

Hey there!

x=(4/5)*15=12

Hope this helped :)

Hey there!

Area of square big: 25x^2

Area of square small: 4x^2

Area of triangle: (10x^2)/2=5x^2

From this we can just solve for x

850=25x^2 + 4x^2 +5x^2

850=34x^2 

25=x^2

x=5 inches

Hope this helped :)