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Because there are 5 teachers on the committee, there are 6 non-teachers. Now, in total, we can form (11 \choose 4) = 330 subcomittees. The number of subcommittees with zero non-teachers is the number of subcommittees formed by the 5 teachers, totaling (5 \choose 4) = 5. So, the number of subcomittees with at least one non-teacher is 330 - 5 = 325

1: The shorter leg on the triangle is 3 units long.  So the area of a square with that side length is ___________.

   A  square has equal lengths so a square with that side lengths is 3x3 = 9

2: The longer leg on the triangle is 4 units long.  So the area of a square with that side length is _________.
 

   Same thing, plug the side length to the square. 4x4 = 16

3: Therefore, the hypotenuse is 5 units long.  So the area of a square with that length is ________.

     I'll let you try this one. (Hint):  (length^2)

Hello, Guest! Are you gonna thank me too although my answer is different? 

Base = 4 ¹/₄ ft

See here  : https://www.desmos.com/calculator/oe0gaxs2tt

The  solutions  are    ( ≈ -5.046, ≈ 10.604)  and  ( ≈ 1.189, ≈ 6.151)

2x^2  + 7x  -  5  =  (-1/3)x^2  - 2x  + 9                   multiply through  by  3

6x^2  + 21x  - 15  =  -x^2  - 6x  +  27              rearrange  as

7x^2  +  27x - 42  =  0

Use  the  quad  formula  to get

x =       -27 ±   sqrt   [ 27^2  -  4 (7) ( -42) ]

          ______________________________

                            2  *  7

If  you  calculate  this  correctly  you  should get  the  solutions for   x   shown by  the  graph.....

Yup, the "x" is supposed to be there. Thanks EP!

Area  of  square  =  (side length)^2

Can  you  go from here   ????

Let R  be  the  full speed....note  that 5 min   = (1/12) hr

And  rate  * time  =  disttance.....so.....

R(1/12)  + (R/2)(1/12)  +  (R/4)(1/12)  =   28

(1/12)  ( R  + R/2 + R/4)   =  28           multiply  both sides  by 12

(R  + R/2  + R/4)  =  336

( 4R  + 2R  + R)  / 4   =  336      multiply  both sides  by  4

7R   =    1344

R =  1344  / 7  =   192 km / hr

Area of a rectangle    =  l x h

   28 x    =    l * 8

   28x = 8L

    L = 28x/8 = 7x / 2  

Perimeter =   8   +  8   +   7/2 x   + 7/2 x  = 16 + 7x                ( is that 'x' supposed to be in there????)

Call the speed s km per minute. 

Then in the first 5 minutes, 5s km are traveled. 
 

In the second 5 minutes, in half speed, we have s/2 km per minute, so 5s/2 km traveled. 

In the third 5 minutes, we have quarter speed, or s/4 km per minute 5s/4 km traveled. 

5s + 5s/2 + 5s/4 = 28 km total. 

5s + 5s/2 + 5s/4 = 35s/4

35s/4 = 28

s = 28*4/35 = 16/5

So the full speed is 16/5 km per minute or 192 km per hr

Thanks!

Height  after   w    weeks  :

H  =  25  +  2.5 (w)

After  4  weeks :

H =   25  + 2.5 (4)   =     35  inches

We  have a trapezoid   with  a height of  3  and one  base  of  7.2

To  find  the  missing  base , B  :

17.175  =  (1/2) (3)  (7.2 + B)

17.175   = (3/2)  ( 7.2 + B)

17.175  (2/3)  - 7.2   =  B   =  4.5 (ft)

Another possible  answer

m =  (24 / 10) r

"Suppose m is the amount of money the students collect for selling R raffle tickets."

We know that every time they collect an amount they receive an amount. So the equation would look something like this:

Rx = mx   (The number being next to it shows it being multiplied)

The "x" represents the amount they sold.  

Hope this helps! :D

(Also, if they want you to write the "m" as "M" make sure to change it before answering thank you!)

7 dozen pairs  =  7 * 12  =   84 pairs

Unit  price  =   Total cost /  Total number  of pairs  purchased  =   102.48  /   84    =   $1.22

The error  is that  he  divides   102.48 / 7  =  14.64  =  the  cost for a dozen pair,  not  one pair

No  prob   !!!

Estimate  =   55 * 7   =   385  seconds

Exact  =    54.8  * 6.9   =   378.12  seconds  

Well if ur solving for x, then 2x² + 7x - 5 = -1/3x² − 2x + 9

\(2x^3+7x-5=-\frac{1}{3}x^2-2x+9\)

\(=6x^3+21x-15=-x^2-6x+27\)

\(=6x^3+21x-42=-x^2-6x\)

\(=6x^3+27x-42=-x^2\)

\(=6x^3+x^2+27x-42=0\)

\(=x\approx \:1.15942\dots \)

Thank you so much

10pi/3   =  3pi +  pi/3    =   pi + pi/3   =  (4/3)pi  =  240°

(cos 240° , sin 240°)   =    (-1/2 ,  -sqrt (3)  / 2 )

fission, fragmentation, and budding are 3 methods of asexual reproduction.

From the problem, we have this information:

Kenn took 2/7 of the treats

and Ben took 5/7 of the treats

If Kenn took 18 fewer sweets than Ben, how many sweets did they have altogether at first?

First, we figure out how much more Benn took from the pile than Kenn. 

We take Ben's total and subtract it from Kenn's total. Putting that in number form it looks like this:

5/7 - 2/7

Thankfully, it has the same denominator so we can subtract 5 from 2 which is 3.

Now we know that Ben has 18 (or 3/7) more treats  than Kenn so we divide 18 and 3 to figure out 1/7 of the fraction which is 6
(because 6 multiplied by 3 is 18)

So now we know 1/7 is 6 we just have to multiply 6 by 7 to get our total. Multiplying it gets you 42

So in total, they had 42

Hope this helps! :D



 

If we know that there are 45 people per square kilometer and there are 33 square kilometers we can make this equation:

45 * 33 = y

(the * is another way write multiplication) 
 

All we have to do is multiply the numbers!

45 x 33 = 1,485

I hope this helps! :D