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No and no but I bet you have

Wrong person I guess

Let  M  be   the  number  of pennies  that  Mickey  has  initially

Then  (6/5)M  =  Skid's  pennies  originally

So

(6/5)M  -  (1/2)(6/5)M  +  15   =  M  + (1/2)(6/5)M    simplify

(6/5)M  + 15  =  M  + (1/2)(6/5)M  + (1/2)(6/5)M

(6/5)M  +  15 =  M   +  (6/5)M

15  = M  =  the number  that Mickey had originally

(6/5)(15)  =  18  =  the number that  Skid  had originally

Proof ....when Skid  givess 1/2 of his pennies to Mickey.....Mickey has  15 + 9  = 24 pennies  and Skid  has  9......so.....Skid  has 15 fewer pennies than Mickey

What u talking about?

Have you ate a s**t

Thank You for the help melody but that isn't right and what they mean for A/XYZ is like the total area over XYZ' area. Thank you for he attempt.

No in fact I have NOT fuked myself

Is that you

Have you fucked yourself 

sqrt  [ 1^2 + 4^2 ] =  sqrt  (17)

sqrt [ 3^2 + 5^2 ]  =  sqrt (34)

sqrt  [ (-6)^2  ]  =  sqrt (36)

sqrt [ (-4)^2 + (-2)^2 ]  =  sqrt  (20)

(0, -6)  is  the point most distant from  the origin

First have you tried to solve it?

This is 2 different things

You says it's easy  so you have to show me proof.

Why should I?

Answer it 

Did it work? (if you even saw it)

Its not confusing. Its really easy to be honest.

Anyone know?

I posted it 

I took it  that  j   and k are  different integers....however....if  they can be  the  same, then you are correct , EP

The  sum of all  possible k's would then be   12 + 4 + 6   =  22

I wonder if they can BOTH be 6 ?

1/j  + 1/k   =  1/3

Let  3  =  z

j and  k  must  be >  3

So

Let   j  =  z + m      and   k =   z  +  n

So  we  have

1/ ( z + m)  +  1/ ( z + n)  =  1/z

(z +n  + z + m)            1

____________  =     ____                 cross-multiply

(z + m) (z + n)             z

(m + n + 2z) z  =    (z + m) (z + n)

2z^2  + zm + zn  =  z^2  + zm + zn  +  mn

z^2    =   mn

3^2 =  mn

9  = mn

Either   m  =  9  and  n =  1   or    m = 1  and  n = 9

If  m  =  9  then   j = z + m  ⇒  j = 3 + 9   =  12

And n  = 1  then k = z + n  ⇒  k  = 3 + 1  =  4

So  (j, k)  =  ( 12, 4)  or  (4, 12)

So....sum of  all k's  =   12 + 4   =  16 

404   Ooops  Page not found

Can you not post the question directly on the forum and not use links?

Basically, the entire volume of A is now in B when done

volume of A   = pi r^2 h  =  pi (5^2)19 =~ 1492.36 ft³     = volume in B when all of A is transferred

         ( B has volume of  1847  ft³     so all of A will fit)

oof I don't know why