All Answers

#40

+129839

0

Wow...that's pretty amazing !!!!

CPhillApr 25, 2021

#39

+73

+1

7 remaining

67

69

83

84

86

87

93

MatherewApr 25, 2021

#1

+129839

+1

floor x = 15

Solutions for x

15 ≤ x < 16

So

15 - 2 ≤ x - 2 < 16 - 2

13 ≤ x - 2 < 14

CPhillApr 25, 2021

#1

+129839

+1

1/a + 1/b = 1/6

a, b must be > 6

So.....let z = 6 a = z + m b = z + n

So we have

1/ ( z + m) + 1/ ( z + n) = 1 / z simplify

z [ 2z + m + n) = (z + m) (z + n)

2z^2 + zm + zn = z^2 + zm + zn + mn

z^2 = mn

6^2 = mn

36 = mn

m n a = z + m b = z + n

1 36 7 42

2 18 8 24

3 12 9 18

4 9 10 15

6 6 12 12 (reject this)

So...we can wirite 1/6 as the sum of four different pairs of unit fractions

CPhillApr 25, 2021

#1

+129839

+1

(0,3) and (1,5) are on the graph

Slope = (5 -3) / ( 1 - 0) = 2 / 1 = 2

Using (0,3).....the equation of the line is

y = 2x + 3 re-write as

2x - y = - 3

CPhillApr 25, 2021

#2

+16

-1

THANKS A MILLION!!!

luckystar042003Apr 25, 2021

#1

+129839

0

See my answers under your earlier post, Luckystar

CPhillApr 25, 2021

#1

+129839

+2

a) (55-60 ) / 3.4 = - 1.47 = .0708

(106 - 110 /6.8 = -.588 ≈ .2810

He did better on the aptitude trst

b) ( 67 - 60) / 3.4 = 2.65 = .996

(119 - 110) / 6.8 = .132 = .5517

She did better on the knowledge test

c ) -.43 = .3336

He did better on the logic test than on the other two tests

CPhillApr 25, 2021

#1

+129839

+1

1 2 3 4 5 6 7

_____________________

1 2 3 4 5 6 7

2 2 3

3 2

4

5

6

7

We have C(7,2) = 21 possibiities

Only 9 meet the criteria

So

9 / 21 = 3 / 7

CPhillApr 25, 2021

#1

0

(a,b) = (22,12)

GuestApr 25, 2021

#1

0

The probability is pi/8.

GuestApr 25, 2021

#1

+129839

+2

( x - 23)

_______ = 1.25

3.8

x - 23 = 1.25 (3.8)

x - 23 = 4.75

x = 4.75 + 23 = 27.75 = Allan's BMI

CPhillApr 25, 2021

#1

0

By Hamilton's Theorem, the solutions are z = 4^{1/4}*e^(pi*i/4), 4^{1/4}*e^(pi*i/4 + pi/4), 4^{1/4}*e^(pi*i/4 + 2*pi/4), and 4^{1/4}*e^(pi*i/4 + 3*pi/4). Since 4^{1/4} = sqrt(2) and e^(pi*i/4) = (1 + i)/sqrt(2), the first solution is 1 + i. Then the other roots work out as

4^{1/4}*e^(pi*i/4 + pi/4) = 1 - i,

4^{1/4}*e^(pi*i/4 + 2*pi/4) = -1 - i, and

4^{1/4}*e^(pi*i/4 + 3*pi/4) = -1 + i.

GuestApr 25, 2021

#1

+129839

+3

3. Last year, the numbers of skateboards produced per day at a certain factory were normally distributed with a mean of 20,300 skateboards and a standard deviation of 52 skateboards.

(a) On what percent of the days last year did the factory produce 20,404 skateboards or fewer?

Calculate the z score = ( 20404 - 20300) / 52 = 2

The z score translates to .9772 = about 97.7 %

(b) On what percent of the days last year did the factory produce 20,248 skateboards or more?

Calculate the z score = [ 20248 - 20300 ] / 52 = -1

The z score translates to = .1587

So....the % days that they produced 20,248 skateboards or more = 1 - .1587 = .8413 = about 84.13%

(c) On what percent of the days last year did the factory produce 20,196 skateboards or fewer?

z = [ 20196 -20300 ] / 52 = -2

The z score translates to . 0228 = 2.28%

CPhillApr 25, 2021

#1