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The answer is 210.

You must be at least 108 feet of framing.

1. The area of the parallelogram is 3*sqrt(5).

2. The point of intersection is (3,-7,-1).

$P = \log_3 1004$, so $a + b = 3 + 1004 = 1007$.

1. There are 5,280 more licenese plates available.

2. There are 18 possible seatings.

3. There are 15 possible values of X + Y.

a/b = 8.

1. There are 43,860 more license plates available.

2. There are 42 possible seatings.

3. There are 24 possible values of X + Y.

There are 270 triples.

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We can convert this problem into a simple algebra problem.

if we make the second train equal to X, then the first train will be X+22

And since the trains are coming towards each other, we can and these numbers together, to get 2x+22

So, the MPH of the trains is 2x+22.

Since the trains meet in 5 hours, we can divide 1130 by 5 and get 226, and we know that 2x+22=226.

From here, it is easy 2x is equal to 204, and x is equal to 102,

so the rate of the first train is 102+22, and the second train is 102, so the rate of the two trains is 124, and 102.

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The real values that are not in the domain are 1, -4, and -5.

n = 12.

PV = (-1,8,2).

The product is 2.

q(-1) = 4.