That is a tough one !
Angle B is 21 degrees.
(x_1,x_2) = (-2,3).
The remainder is 6.
z = 7 + 8i.
Height x average base
6 x (12+15)/2 = 81 cm2
corrections:
GF / BF = CH / BH
GF = (BF * CH) / BH
[CDEFG] = (CH * BH) - (GF * BF)
It is a dell laptop
Press win button then prt scr works for me with windows 10
DE / AE = CH / AH
[CDEFG] = (CH * AH) - (DE * AE)
The possible values are 0, 1, 2.
You shouldnt need Win + Prnt Scr. Do Win + Shift + S for an area screenshot. Or, press Prnt Scr by itself and find it in your pictures folder.
First find the value of 'x' not 'X'
9x+18 + 5x+15 + X = 15x + 3x+21 + X
4x -12 = 0
x = 3
then for triangle vxu 3(3) +21 + X + 15(3) = 180 show X = 105 degrees (this is VXU)
You know you can ask question on bartleby.com
[ADE]/[ABCD] = 1/6
Try ctrl and prtscrn
1. AC = 24.
2. XY = 6.
3. The smallest possible perimeter is 4*sqrt(3).
Oh it makes sense now! I only had issues when it came to the part when there was the 3^2, so I must've forgotten a log rule there.
The domain can be any x EXCEPT for x's that cause the denominator to be equal to or less than 0
x cannot equal 1 or -1 or any value between
(-inf,-1) U (1,+inf)
x=6
Log3 ((x+3)(x-5) ) = 2
log3 (x^2-2x-15) = 2
x^2 - 2x - 15 = 3^2
x^2 -2x-24 =0
(x-6)(x+4) = 0 x = 6 or -4 (throw out....cannot have log of a negative )
a^2 + b^2 = 43/3.
1 - There are 180 integers with at least one "zero".
2 - There are 8 ways of making up 45:
N D Q
1 = 9 0 0 2 = 7 1 0 3 = 5 2 0 4 = 3 3 0 5 = 1 4 0 6 = 4 0 1 7 = 2 1 1 8 = 0 2 1
please help!
Thanks! I got it now. :D
The quadratic looks like this: (x+99 + sqrt(8021) (x +99 - sqrt(8021)
The value of 'c' will be (99 + sqrt8021)(99-sqrt8201) Expand......