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5^2x+3= 5^x * 5^x * 5³      Now can you solve it (knowing 5^x = 3)?

a + b + c + d = 45.

Janice bought 18 30-cent items.

The are reflective. (7,4) (4,7)

The domain is (1,inf).

1. By complementary counting, there are 999 - 111 - 11 - 1 = 876 such positive integers.

2. There are 6 possible combinations.

The area of the circle is 1944*pi.

The shortest distance is 10.

There are three possible values of a: 0, 32, 36.

Nice :))

=^._.^=

THANK YOU SO MUCH

ANSWER= $48000

x = original salary

1.16 x = salary after increase

1.16 x = 55680    solve for x

x = 55680/1.16 = $_____________

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See if you can understand why...

Umm.... thanks for your answer but you know the question clearly says not to use graphing, right? 

180 all together

all end up with the same (60 each)       so   C - 1/3 C = 60

                                                                     C = 90    stamps originally

\(QED = (11-5i)(3-2i)(2i)\)

We can split this up into two parts. Let's first compute \((11-5i)(3-2i)\), and then multiply it again by \(2i\).

\((11-5i)(3-2i) = 11(3-2i)-5i(3-2i) = 33-22i-15i+10i^2 = 33-37i-10 = 23-37i.\)

\(2i\cdot(23-37i) = 46i-74i^2 = \boxed{74+46i}\)

The width of the domain of g(x) is 4.

The greatest integer value of b is 12.

The area of CDEFG is 272.

Just illustrating catmg's answer about the dice.  

The following shows all possible rolls of the dice.  

Anything with a 1 or a 4 satisfies the condition.  

You can see by counting, there are 20 of them.  

And 20/36 reduces to 5/9.   Good work, catmg.  

     1,1   1,2   1,3   1,4   1,5   1,6  

     2,1   2,2   2,3   2,4   2,5   2,6  

     3,1   3,2   3,3   3,4   3,5   3,6  

     4,1   4,2   4,3   4,4   4,5   4,6  

     5,1   5,2   5,3   5,4   5,5   5,6  

     6,1   6,2   6,3   6,4   6,5   6,6  

_.

(4 - 5i)(5 + 5i)    expand

20 + 20i - 25i- 25i^2

20 -5i + 25

45-5i

He SHOULD have gotten   3+ 7i

(x-1-sqrt2)(x-1+sqrt2)(x-2-sqrt5)(x-2+sqrt5)      this equals  x⁴-6x³+6x²+6x+1

Rationalize the denominator by multiplying by   (1-3i)/(1-3i)    to get      (9+13i)/10