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I think 43/3

since there are 17 heads there are 17 animals so far in our count

   20 legs means 5 cows

      then   there are   17-5 = 12 octipi

             196 tentacles    12 octipi * 8 = 96 tentacles are octipi   the remaining tentacles are jellyfishes 196 - 96 = 100

                             100 / 20 = 5 jellyfish

total 22 animals

PANIC

(a + b) =  7       cube both sides

a^3  +  3a^2b + 3ab^2  + b^3    =  343

a^3 + b^3   + 3ab ( a + b)    =  343

42  + ab  +  3ab ( 7)   =  343

42   +  22ab  =  343

22ab  =  301

ab  = 301 / 22

And

1/a  + 1/b =    [ a + b ]  / ab  =     7 / ( 301/22)   =  22 * 7  / 301   =  154 / 301  = 22  / 43

catmg is correct .....see   the graph here :  https://www.desmos.com/calculator/yyanrxdkr3

Is Abcyacomga a hated person     

A B C D puppies 

M R not puppies 

O S M R 

C M P N 

The polygon has 28 sides.

cos AMN = 5/6.

Farmer Brown has a total of 24 animals.

sine(x)*cot(x)

sine(x)*cos(x)/sine(x)

cos(x) = -2sqrt(2). 

However, cos(x) must be in the range -1 to 1. 

I think there aren't any answers. 

=^._.^=

I don't get it, -6/1 is still -6? or am I missing something here?

Homer is giving some cookies to each of his three brothers. To the oldest, he gives half of the cookies and half a cookie. He then gives half of what is now left and half a cookie to his second brother. Finally, he gives half of what is now left and half a cookie to his third brother. At no time is a cookie broken or cut. How many cookies did Homer have to begin with? 

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

IF Homer had 100 cookies, he would give 50.5 cookies to his oldest brother, 25.25 to his second brother, and 12.625 to his third brother.

The ratio of given cookies is as follows:   50.5 : 25.25 : 12.625     or     4 : 2 : 1

So, Homer had 7 cookies, and he gave them all to his brothers:

Oldest          3.5 + .5 = 4

Second        1.5 + .5 = 2

Third              .5 + .5 = 1

No cookie needed to be broken! 

We  have two equations 

(G - x ) / B  =   3/2     ⇒     2(G - x)  =  3B  ⇒  2G - 2x  =  3B  ⇒  (28/3)G - (28/3)x =  14B   (1)

G  /( B - x)  =  14   ⇒  G  = 14(B - x)  ⇒  G = 14B  - 14x  ⇒  14B =  G  + 14x   (2)

Equating (1)  and (2)

(28/3)G  - (28/3)x   =  G + 14x

(25/3)G  =  (70/3)x

25G  = 70x

LCM  25, 70    =  350

25G  =350    and  70x  = 350

We  have  an equality  when   G = 14   and  x  =  5

So

2G - 2x =  3B

28 - 10  =  3B

18  = 3B

6 = B

Proof

(14-5) / 6  =  9/6   =  3/2

and

14  / ( 6 - 5)  =     14  / 1 

Ratio of B /G   =   14 / 6   =   7 /  3

Or https://www.quora.com/Sarah-and-Henry-share-some-sweets-in-the-ratio-of-7-6-Sarah-eats-12-of-her-sweets-and-the-ratio-of-sweets-left-becomes-1-2-How-many-sweets-did-Henry-have

S + H = N

(5/11)N = s and (6/11)N = H <--- they are in the ratio 5:6 ; She has 5/11 of them and he has 6/11 of them.

She eats 24:

S-24 = (1/3)(N-24) <---Now the ratio is 1 to 2, so she has 1/3 of the remaining and he has 2/3

H = (2/3)(N-24)

H= (6/11)N = (2/3)(N-24) <-- Henry's amount does not change. so the two equations are equal.

18N = 22(N-24) <--- multiplies both sides by 33 to clear away the fractions

18N = 22N - 528 <--- distributive

0 = 4N - 528 <-- subtracts 18N from both sides

528 = 4N <--- adds 528 to both sides

N=132 <--- divides by 4

132 at the beginning....

She has 5/11*132 = 5 * 12 = 60 and he has 6/11 * 132 = 6 * 12 = 72.

She eats 24.

She then has 36 and he still has 72, which is in the ratio 1:2

Henry has 72 sweets

cited from wyzant

a = 17/2.

I got 14 1/4 

Square side = a

Perimeter  P = 2[(35 - a) + (15 - a)] + 4a

P = 100

Thank you so much 

The denominator of the original fraction is 20.

Jamie found a bag containing 56 coins. There were 4 times as many quarters as half dollars. There were 3 times as many dimes as half dollars. How many fewer half dollars were there than quarters?

Let  the  number of  half-dollars =  H

Number of  quarters  =4H

Number of dimes = 3H

So

H  + 4H  + 3H   =   56

8H  =  56

H = 56/8   =  7

Number of quarters = 4(7)  = 28

28  - 7    =  21  fewer half-dollars  than quarters

t = 1/2(172 - 152) = 10

s = 43 - 10

Homer is giving some cookies to each of his three brothers. To the oldest, he gives half of the cookies and half a cookie. He then gives half of what is now left and half a cookie to his second brother. Finally, he gives half of what is now left and half a cookie to his second brother. At no time is a cookie broken or cut. How many cookies did Homer have to begin with? 

Let  the  total  number  of  cookies =  T

He  gives  the oldest  T/2  + 1/2

What  is  left  after  this  is  T  - (T/2  +  1/2)  =  (T/2) - 1/2

He  gives  the next brother  (1/2) ( T/2 -1 /2) + 1/2  =  T/4 + 1/4

What is left is  [  T/2  - 1/2 ] -  [ T/4  + 1/4 ]    = T/4 - (3/4)

He  gives  the last  brother  (1/2)  [ T/4  - (3/4)]  + 1/2   =  T/8 + 1/8

Now  the  sum of what  he gives  to each  brother  must  be  the  total number  of cookies

So....we  have  this  equation

T/2 + 1/2    +   T/4  + 1/4   +  T/8 +  1/8    =  T       simplify

(7/8) T  +  (7/8)   = T

(7/8)  =  T(1 - 7/8)

7/8  =  T/8

7  =  T     = the  number  he statred with

Proof

He  gives the oldest  (1/2) 7  + 1/2 =   4

3 are left

He  gives  the  next     (1/2) 3  + 1/2   =  2

1 is left

He  gives  the last  brother  (1/2) 1  + 1/2  =  1

The value of c is 23.