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I believe Yeager is correct since the external angle of an equiangular polygon could be the angle that is supplementary to the interior angle.

There are 2 definitions for exterior angles, and as Melody said, one of the definitions (360 - interior angle) will make the problem have no solutions.

OMG THANKS!!!! 

85.3973422267

Let  the  number  that  Jack  solved  =  N

Then John solved  2N +  1

So

N  + 2N +  1  =   28

3N   =  28  -  1

3N  =   27

N =  27  / 3    =  9   =   number Jack solved

2(9) + 1   =  19  =  number John solved

See  the  graph   here  :    https://www.desmos.com/calculator/xkyg3ldml5

The  graph will pass through  2  lattice  points  every  time  x  changes  by  1

So....it will pass trough    2(14)  +  1   =   29 lattice points   

The problem  is  in the  set -up

sin ^2  x   +   cos^2   x   =   1

But

(-sqrt (2)  / 2)^2    +   ( sqrt  (3)  / 2) ^2  =

         2/4     +  3/4      =     5/4 

  { The  sine  should   probably  be   -1/2   to  make  this work }    

this is the

 image

D

There's a square root on the denominator of the solution.

multiply top and bottom by $\sqrt3$

We  are  drawing   segments   ("diagonals")  from  one vertex  to  each  of ( 11 - 3)  =   8  other  vertexes  ( we  are already connected to the  two adjacent  vertexes)

The  number  of  triangles  formed  =  (11 - 2)  = 9

The  area  =   9 * 15    =    135

2 or 6,8,2 or 6, 1/2 or 2

here are a few that are a little similar:

89+0$\cdot$(1+2+3+5+6)+4+7=100
89+0$\cdot$(1+2+3+4+7)+5+6=100

78+9$\cdot$2+3+1+0$\cdot$(4+5+6)=100
 

you can make some more off of that.

1.   1 + (1/2)(12)

      1  +     6         =     7

2.   (3/4)(4)   - (2/3)(3)   +  (2/3)(9)

         3         -    2          +      6          =    7

3.   2  - (15/3 ) +    10

       2    -   5    +    10

            -3        +     10    =    7

4.  [ (1/2) ( 6 - 2) ]   +   [ (1/2) ( 12  - 4)]   +   1

     [ (1/2) (4) ] +  [ (1/2) (8) ]   + 1

            2       +    4        +     1      =     7

5.   (70 / 14) (2)   -  (42/7)(1/2)

           5(2)   -   6(1/2)

           10     -    3       =     7

A is the answer

mynameismrcheese

Pls help as soon as you can!!!!!!!!!!!!!!!

1. Adding , subtracting fractions  -  get a  common denominator

2.   Multiplying fractions  -  multiply  numerators  together  and  denominators  together

3. Dividing  fractions  -   keep  the first fraction , flip  the second,  multiply

Fib  :   We need  to get a common denominator  in  multiplying  and dividing fractions

See  here :  https://web2.0calc.com/questions/trapezoid_21

x/4   +  y/18   =   1         multiply  through  by  LCM  4 , 18   =  36

9x   + 2y  =  36

2y  =  -9x  + 36             divide through  by  2

y  = (-9/2)x  + 36/2

y  =  (-9/2)x  +  18

Slope  =  -9/2        y  intercept  =  18

x int :       0  =  (-9/2)x  + 18

              -18  = (-9/2)x

             (-2/9)(-18)  = x

                      4  =  x

So

a  +  b  +  m     =

4  + 18   -  9/2    =

22  - 4.5  =

17.5

We can write -4 in exponential notation as 4e^(pi*i), so the equation is z^4 = 4e^(pi*i).

By Hamilton's Theorem, the solutions are z = 4^{1/4}*e^(pi*i/4), 4^{1/4}*e^(pi*i/4 + pi/4), 4^{1/4}*e^(pi*i/4 + 2*pi/4), and 4^{1/4}*e^(pi*i/4 + 3*pi/4).  Since 4^{1/4} = sqrt(2) and e^(pi*i/4) = (1 + i)/sqrt(2), the first solution is 1 + i.  Then the other roots work out as

4^{1/4}*e^(pi*i/4 + pi/4) = 1 - i,

4^{1/4}*e^(pi*i/4 + 2*pi/4) = -1 - i, and

4^{1/4}*e^(pi*i/4 + 3*pi/4) = -1 + i.

1  -  2/3    =   1/3   left

(1/3)  / 3   =    1/9   =  what each friend got

In  one fell  swoop  we  have  ( 1 - 2/3)  / 3     =   1/9