All Answers 356371 Answers

The numbers do not add up.....      1/2 + 1/3 + 1/4 = 13/12       which is greater than 1 whole .....

  the approximate numers of each would be

      60 * 1/2 = 30 marigolds

      60 * 1/3 = 20 pansies

      60 * 1/4 = 15 petunias      ( which adds to 65 plants  because the fractions add to more than one)

It says that it is wrong...

Could you please explain the method?  I entered the answer into the website I am using, but it says the answer is incorrect.  

Initially

  b = 1/5 j

then

b+4   = 1/3 (j-4)     sub in the first equation

1/5 j + 4 = 1/3 (j-4)

4 + 4/3 = 1/3j - 1/5j

j = initially = 40                      then she gave away 4   to have 36 books at the end

2 out of (2+1) were circles      2/3 of the total were circles     the rest were squares

2/3 * 27 = circles = 18

    the rest are squares = 27 - 18 = 9 squares

https://web2.0calc.com/questions/percent-question_14

1. The solution is (-inf,-8] U [1,inf).

2. The solution is (2,inf).

Here is most of it.....see if you can finish  knowing that the angles of a triangle sum to 180

     opposite angles of crossing lines are equal

        the sum of interior angles of a 5-gon = 540

Check to make sure I made no mistakes !    ~ EP

U so smart!!!!

DOUBLE  Yayy!  catmg   and  I   got the same result ! !       ( or we made the same mistakes....LOL)

In rectangle ABCD, parallel lines k and m through A and C are perpendicular to diagonal BD and divide it into three equal segments of 1. What is the area of rectangle ABCD?

Hello Guest!

\(y^2-1^2=x^2-2^2\\ x^2+y^2=3^2\)

\(y^2=\\ x^2-2^2+1^2=3^2-x^2\\ 2x^2=3^2+2^2-1^2\\ x^2=12/2\\ x=\sqrt{6}\\ y^2=9-x^2\\ y^2=9-6\\ y=\sqrt{3}\)

\(A_{ABCD}=\sqrt{3\cdot 6}\)

\(A_{ABCD}=3\cdot \sqrt{2}\)

(u^2 + v^2)/(u^2*v^2)

((u+v)^2-2(uv))/((uv)(uv))

By vietas, u + v = -5/3, and uv = 7/3. 

Take it from here. :))

=^._.^=

Converting everything to 3. 

3^(2y) = 3^(5) * 3^(12) * 3^(16) * 3^(-9)

3^(2y) = 3^(24)

2y = 24

y = 12

Yayyyy, EP and I got the same answer. :))

=^._.^=

Thanx, Chris !!         ~ EP

42 students      10% more girls

            B  + 1.1B = 42

                B = 20      then G = 22

x girls go the bathroom and

B      =     1.25 (22-x)

20    =      27.5 - 1.25x

x = 6   girls went to the can

L = 1.75 J     This is given

Then J gives away    'g'

J - g = .25 J

   .75J = g

Liam gave away 200% or   2 g     which is    1.5J

L = 1.75J   originally      then subtract   1.5J

  L_new = .25J

       so the fraction Liam has at the end is    .25J / 1.75J = 1/7

(3^2)^y = 3^5  *  (3^2)^6   *  (3^4)^4  / (3^3)^3

3^2y     =  3^5+12+16 / 3⁹

3^{2y     =}  3³³ /3⁹  

3^2y   =  3²⁴            now equate the exponents and solve for y

2y  = 24

y = 12                 (IF I made no errors......check my work ! )

BEFORE it is drained ,  t  will be = 0

V = (-255)(0) + 656420

V = 65420 liters

Just plug in to the equation

(y-2) = 5 (x-4)  

Class C = x

Class B = 1.6*x

Class A = 1.5*1.6*x = 2.4x

2.4x/x = 2.4

=^._.^=

You're welcome, all the end numbers repeat. :))

1: 1, 1, 1, 1

2: 2, 4, 8, 6

=^._.^=

Not sure how the first part is relevant. 

7 * g = 19

g = 19/7

=^._.^=

The probability is 4/9.

x = 1 + x/(2 + x/(2 + x/(2 + x/(2 + ...))))

x - 1 = x/(2 + x - 1)

x - 1 = x/(x+1)

x^2 - 1 = x

x^2 - x - 1 = 0

Solve for x :))

=^._.^=

For there to be 2 rational roots, the derivative has to be a positive square. 

(17^2 + 4c) is a positive square like (1, 4, 9, 16...)

Take it from here. :))

=^._.^=