[6060 / 6 - 6930/9] ==[1010 - 770] / 2 ==120 mph - the rate of the wind.
[1010 + 770] / 2 ==890 mph - speed of the jet in still air.
If you let x go infinity, then you get 0 = A + B.
If you let x = 0, then you get 7/2 = A/(-2) + B.
The solution to this system is then A = -7/3, B = 7/3, so (A,B) = (-7/3,7/3).
A = 2.5(G-7)
B = G-7
G = G ()
2.5(G-7) + G-7 + G = 142
G => 37 kg
A => 75 kg
B => 30 kg
a - The value of r escaltes with each new term. It begins with: 1/2 and then it increases by 1/4 for every term thereafter to; 3/4, 1, 1 1/4, 1 1/2, 2........etc.
b - What this tells you is that the series diverges to infinity.
$-2(x^7 - x^4 + 3x^2 - 5) + 4(x^3 + 2x) - 3(x^5 - 4) = -2x^7 - 3x^5 + 2x^4 + 4x^3 - 6x^2 + 8x - 2$.
The sum of the coefficients is then (-2) + (-3) + 2 + 4 - 6 + 8 - 2 = 1.
Let a be the speed the jet travels, and let b be the speed the wind travels.
$9(a-b)=6930$
$a-b=\frac{6930}9=770$
$6(a+b)=6060$
$a+b=\frac{6060}6=1010$
$a+b=770$
$a-b=1010$
You can finish the rest :)
You can move 3pi/2 and 9pi/13 to one side, and add them together, and then you can cross multiply, it's basic algebra.
6th piggy bank = 3 * 81
Don't think i have the time to show the steps, but the sum of the possible solutions of that equation is 0.
By the Binomial Theorem, the constant term is 12.
By Cauchy-Schwarz, the minimum value is 1/n.
BI = 4*sqrt(3).
x + x + 35 = 685
2x = 650
x = 325.
Q4 the i unit Q2
a = 2.5 b
g = b-7
b summed = 142
2.5b + b-7 + b = 142 solve for b... then g = b-7
x^2 +2x +6 = 0 in simplified form
Use quadratic formula with a =1 b = 2 c = 6
\(x = {-2 \pm \sqrt{2^2-4(1)(6)} \over 2(1)}\) Calulate away to find a and b then you can finish ....
g(x) will also be of degree 5 such as :
-2 x^5 + x^4 + x^3 this will eliminate the 2x^5 and -x^4 terms in f(x) and leave a x^3 term in the sum of f and g
Thank you so much for the answer, lifesaver! But can someone show me how you got there?
If f(x) and g(x) are polynomials such that f(x) + g(x) = -2 + x, then what is g(x) if f(x) = x^3 - 2x - 2 - 4x^2 + 8x - 7?
Hello Guest!
\(f(x) = x^3 - 2x - 2 - 4x^2 + 8x - 7\)
\(f(x) + g(x) = -2 + x\)
\(g(x)=-2+x-( x^3 - 2x - 2 - 4x^2 + 8x - 7)\)
\(g(x)=-x^3+4x^2-5x+7\) \(x=-5,216\)
!
James bought some cans of sardines and tuna in the ratio of 4:5. A total of 22 cans of sardines and 1/2 of the cans of tuna were used. In the end, the ratio of the cans of sardines to the cans of tuna became 1:2. Find the number of cans of sardines that James bought at first.
S : T = 4 : 5
(4x-22)/(5x/2) = 1/2 x = 8
cans of sardines = 4x
BI = √52
I made an error...
1st round 1 - 1/3 = 2/3 (left)
2nd round [(2/3) / 5] * 2 = 4/15 (left)
3rd round [(4/15) / 7] * 3 = 12 / 105 (left)
(a^3b^5)^4 = a^12 * b^20
I think the total number of factors is (12+1)(20*1) = 13*21 = 273
after round one he has 1-1/3 = 2/3 left
after second round he has 2/3 - 3/5*2/3 = 2/3(1-3/5) = 2/3* 2/5 = 4/15
So what does he have after the next round?
If (2x+5)(x-3)=14 + x^2 - 7x, find the sum of the possible values of x.
\((2x+5)(x-3)=14 + x^2 - 7x\\ 2x^2-6x+5x-15-14-x^2+7x=0\\ x^2+6x-29=0\)
\(x=3\pm \sqrt{9+29}\\ x=3\pm \sqrt{38}\)
\(x_1=3+\sqrt{38}\\ x_2=3-\sqrt{38}\)
\(x_1+x_2=6\)
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