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AB = 2*4 = 8 

First runner ==60 + 15 ==75 seconds per lap

2nd runner ==60 + 45 ==105 seconds per lap

LCM[75, 105] ==525

First runner==525 / 75 == 7 laps

2nd runner==525 / 105== 5 laps

So, it will be: 525 seconds ==8 minutes and 45 seconds - when they will cross the finish line at the same time.

What is the minimum number of small squares that must be colored black so that a line of symmetry lies on the diagonal of the square?

Remember, they are using the same dice, so 2,3 is the same as 3,2

It seems correct to me

No! I don't think so. There are: [1, 6], [6, 1], [2, 3], [3, 2] ==4 ways of painting the die !.

Let my age ==A

Mother's age ==25 + A

Father's age ==25 + 3 + A

A * [25 + A] * [28 + A] ==32130, solve for A

Solve for A:
A (A + 25) (A + 28) = 32130

Expand out terms of the left hand side:
A^3 + 53 A^2 + 700 A = 32130

Subtract 32130 from both sides:
A^3 + 53 A^2 + 700 A - 32130 = 0

The left hand side factors into a product with two terms:
(A - 17) (A^2 + 70 A + 1890) = 0

Split into two equations:
A - 17 = 0 or A^2 + 70 A + 1890 = 0

Add 17 to both sides:
A = 17 or A^2 + 70 A + 1890 = 0

Subtract 1890 from both sides:
A = 17 or A^2 + 70 A = -1890

Add 1225 to both sides:
A = 17 or A^2 + 70 A + 1225 = -665

Write the left hand side as a square:
A = 17 or (A + 35)^2 = -665

Take the square root of both sides:
A = 17 or A + 35 = i sqrt(665) or A + 35 = -i sqrt(665)

Subtract 35 from both sides:
A = 17 or A = i sqrt(665) - 35 or A + 35 = -i sqrt(665)

Subtract 35 from both sides:
A = 17 years - my age

17 + 25 ==42 years- Mother's age

42 + 3==45 years - Father's age

Check: [17 x 42 x 45] ==32,130

Guests answer seems reasonable and they had a good way to approach it! (I was trying for ages lol)

Ok my answer for b was wrong and I have to admit it was a very silly mistake on my part. I answered 42 which would have been correct if they asked how many she bought with 1/3 of her remaining money but I forgot to add the amount she bought at the start if I had I would have gotten 50, Sorry again for the incorrect answer and I hope this is the correct answer.

SCZ

Let the number of pounds of $10 coffee==P

10P + 4*20 ==5*[P + 20]

10P + 80 ==5P + 100

10P - 5P ==100 - 80

5P ==20

P ==20 / 5 ==4 pounds of $10 per pound coffee.

5 x 7 x 6 = $\boxed{210}$

If the line of symmetry is the diagonal, then the minimum amount of squares needed to be colored in is 4.

R ==10,000 x (0.985^15)

R==10,000 x  0.79715625....

R ==$7,971.56 - what he had left after 15 years.

Hey Guest! 

Thank you for asking me specifically but as sparkling water said, you don't need to ask for a certain person. 

I'm not quite sure how to approach this problem but this is my best attempt: so each cupcake costs twice as much as a sardine pie, therefore c=2s (c represents cupcake and s represents sardine pie) so the cost of 2 cupcakes and 8 sardine pies is the same as the cost of 12 sardine pies. She then spent 3/4 of her remaining money which is 3/4 of the 4/7 left. This amount is the same as 1/7 of the original amount. The question says that pandan cakes cost 4.50 more than cupcakes but gives no clue as to the other prices. This leaves me at a dead end. You could instead change to amount of sardine pies into cupcakes so the cost of 2 cupcakes and 8 sardine pies is the same as the cost of 6 cupcakes but this still doesn't help us. 

Could someone else try this question? I am new to this website and I do not have a great knowledge of maths so someone else here might be able to help.

SCZ

CORRECT!!!

Hey Guest!

This my attempt at (b) ok so in a we found that 1/10 of her money could buy 14 erasers, its says with 1/3 of her remaining money she bought more erasers after spending 1/10 she had 9/10 left. 1/3 of 9/10 is 3/10 presuming she spent that 1/3 on just erasers with no change then

1/10=14

3/10=14×3

=42

I hope I helped

SCZ

You don't have to ask for one person specifically. Other people can help too, unless this is a problem you specifically want him/her to answer because of something.

Hi Guest! Think of it as an algebra sum but instead of x and y we have pencils (p) and erasers (e) and p=2e (pencils cost double the amount of an eraser) so 

1/10 of her money=8e+3p since p=2e

=8e+3(2e)

=8e+6e

=14e 

So the answer to (a) is 14

SCZ

Hey guest I answered this question here https://web2.0calc.com/questions/help-plz_94058

SCZ

Hey Ticon! So if Jim has 123 multiply it by 2 to get the amount Andrew has 123×2=246 then multiply by 3 to get the amount Robert has 246×3=738 add all the numbers together to get 123+246+738=1107

I hope I helped!

SCZ

Hi guest! I have thought about this question for a bit and since it's says in the first ratio that ad=5 but then it says in the second one that ad=3 it has to be something divisible by 3 AND 5, it says to find the smallest perimeter so ad has to be the lcm of 3 and 5 which is 15, in the first ratio 15 is divided by 3 to get 5 therefore ab has also been divided by 3 so ab=6, applying the same logic to the other ratios 15 was divided by 5 to get 3 therefore cd was also divided 5. If ad=ab then we get

ab=6

bc=15

cd=20

ad=15

Add these together to get 56.

Could someone check this? Idk if I have explained it well

SCZ