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Let f(x) = 2^x.  Find sqrt(f(sqrt(f(f(1)))))

sqrt(f(sqrt(f(f(1)))))

=sqrt(f(sqrt(f(2))))

=sqrt(f(sqrt(4)))

=sqrt(f(2))

=sqrt(4)

=2

a=6 

https://web2.0calc.com/questions/solving-a-system-of-equations

Let Xion has x red stamps.

Adam has 3 times as many red stamps.

         Adam has 3x red stamps.

Again Adam has 6 blue stamps

=) Total no. of stamps Adam = 3x + 6.

Condy has 1/6 the number of red stamps Adam has.

=> Cindy has 1/6 * 3x = 1/2x red stamps.

    Cindy has x/2 red stamps.

   Again Cindy has 3 blue stamps.

   =) Total no. of stamps Cindy has = x/2 + 3.

   Given, that Cindy has 4 stamps fewer than Xion.

       => x/2 + 3 = x - 4.

       =) x/2 - x = -4 - 3

       =) - x/2 = -7

        =) x = 14

        Xion has 14 stamps.

     Adam has 3 * 14 + 6 = 48 stamps

      Adam has 48 stamps.

     Cindy has x/2 + 3 = 14/2 + 3 = 10 stamps.

          Cindy has 10 stamps.

 (a)Total no. of stamps they have altogether = 14 + 48 + 10 = 72

       They have altogether 72 stamps.

 (b)New Xion has 14 stamps and Adam has 48 stamps

      Let Adam gives y stamps to Xion so that they will

          have some stamps.

         => 48 - y = 14 + y

          => 48 - 14 = 2y =)2y = 3y =) y = 17

    Adam must give 17 stamps to Xion so that they'll have 

    same no. of stamps.

Find m+b.

Hello Guest!

\(5x+8y=-9\\ \color{blue}y_1=-\frac{5}{8}\cdot x-\frac{9}{8}\)

\(m=\frac{8}{5}\\ y_2=m(x-x_2)+y_2\\ y_2=\frac{8}{5}(x-10)-10\\ \color{blue}y_2=\frac{8}{5}x-26\\ y_2=mx\ +\ b \)

\(m+b=-24.4\)

  !

ok, sorry

You need to identify yourself next time. 

If you become a member that would be the easiest way.  

Plus if you make a good impression your questions will be answered better and quicker. 

I have not looked at your answer in any great detail but it looks fine to me.  (I don't have my solution anymore)

Thanks Melody

Thanks guys it means a lot and that makes so much more sense

No that's me, I want to see if my answer is right.

i = interest per period =  .059 / 12

p=  periods = what you are looking for (months)

Final amount = 4962

4962 = 4086 ( 1 + .059/12)^p       Solve for 'p' months 

Guest, please do not answer over the top of me.

I give partial answers for a reason and the asker is always encouraged to ask for more help if required.

I do not want this to be just a cheat site. 

I want it to be a teaching / help site.  I think that is what most of the answerers here would want.

If you want to answer a question in full that is fine,  but choose one, of the many, that does not already have a correct partial answer.

Thank you.

Get a common denominator on the RHS

Are the two denominators the same now?  Yes ?

So now equate coefficients on the top

Hi JMaster,

I'm giving you one last chance to be polite.   (not just to me)

You should give yourself a point Mathygoo  

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What is the constant term of the expansion of   \(\left(6x+\dfrac{1}{3x}\right)^6 \)    ?

The general term is 

\(\begin{pmatrix} 6\\ r \end{pmatrix} \displaystyle \left(\frac{1}{3x}\right)^r (6x)^{6-r} \)

You need the term where the power of x is 0

so you need to solve this    \(\displaystyle \left(\frac{1}{x}\right)^r (x)^{6-r} =x^0\)

when you solve for r you can then sub that  r  value into the general term to get the constant that you require.

Thanks Bloom, the graph was a very good place to start.  Give yourself a point (I already have) 

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This question is a lot more involved than I first thought.

This is how I tacked it.  There is more than one way and mine might not be the easiest.

Let a point on the parabola by  \(K(k, k^2-2) \)     Little k is a real constant.

Use pytharoras's theorem to find an expression for the square of the distance between  the origin and K.  Call it D

Now use calculus to find the minimum D

etc

Draw a pic to help you.

I will help more if you work with me towards the solution.   

ie    show what you can do so far and discuss your problems with me.

199!! [This is double factorial] ==6 666308 670072 953744 411215 006735 034163 324489 389674 388736 363184 954745 922258 576896 518414 625915 283128 424390 474317 708176 893511 841954 015267 176587 405666 801912 441638 268530 971962 511539 459228 515625 (187 digits) = 3^49 × 5^25 × 7^16 × 11^10 × 13^9 × 17^6 × 19^5 × 23^4 × 29^3 × 31^3 × 37^3 × 41^2 × 43^2 × 47^2 × 53^2 × 59^2 × 61^2 × 67 × 71 × 73 × 79 × 83 × 89 × 97 × 101 × 103 × 107 × 109 × 113 × 127 × 131 × 137 × 139 × 149 × 151 × 157 × 163 × 167 × 173 × 179 × 181 × 191 × 193 × 197 × 199.

The largest n, as you can see, is ==49

Hello. The constant term is the term in which there is no variable. In your case, that is 160. There is no variable multiplying by it. 

Remember: Variables is an unknown value. 

and a constant is a known value with no variables. 

Pls help quickly

252.5 / (124.7 + 253.5 )      * 60        - 8     = _________min

a+b = 235

a-b =41           Add the equations together then solve for 'a'      then use this answer to solve for 'b'

YZ = 44/7.

k = 32.

The polynomial is $8x^5 - 16x^4 + 12x^3$.

\( {T - 45 \over p} = {1 \over 3}\)
3(T-45) = P

3T - 135 = P

3T - P = 135 --(1)

\( {P - 45 \over T} = {3 \over 5}\)
5(p-45) = 3T

5P=225+3T

5P-3T=225 --(2)

Add equation (1) and (2)

3T-P=135            3-P=135

-3T+5P=225      -3+5P=225

------------------

4P=360

  P=360/4=90

Put P=90 in equation (1)

      3T-90=135

        3T=135+90

          T=225/3=75

P=90

T=90