Questions   
Sort: 
 #3
avatar+118654 
+2

I have commented on Heureka's original answer:

 

https://web2.0calc.com/questions/an-advanced-quadratics-problem

 

Any further content should go on the orginal thread.  Thanks.

 

Just leave a small comment on this thread saying you have added to the other one.

Nov 16, 2021
 #3
avatar+118654 
+2

Thanks for your answer Heureka,

 

This answer has since been questioned here     https://web2.0calc.com/questions/advanced-quadratics-help-pls

so I took a look at what you have done.

 

The only oversight i can see is that since p and q are positive, pq must also be positive

so    pq = 2+sqrt(53)

 

which means that a+b+c+d =161

Nov 16, 2021

1 Online Users