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You have asked a great number of questions.

This is greatly discouraging as it implies you are just getting people to do your homework for you.

Plus you do not even display the pics on the posts or EVEN give links to the addresses.

You are not asking bottom-end questions so I assume this is done, or rather,  not done, only because you are being totally lazy.

It is not a good look.

The smallest possible value of n is 336.

Arc LPM = 360 - 72

What is the measure of arc LOM? 

1*1 squares: only 1

2*2 squares: the black square could either go top left, top right, bottom left, or bottom right, so 4

3*3 squares: also 4, since 5 of the squares would go off-screen

4*4 squares: there is only a total of 4 4*4 squares in the 5*5 square, and all 4 of them contains the black square

5*5 square: only 1 and contains all the squares

1 + 4 + 4 + 4 + 1 = 14

If  1 - sqrt(3)  is a solution,  1 + sqrt(3)  will also be a solution.

If  2 + sqrt(3)  is a solution,  2 - sqrt(3)  will also be a solution.

The polynomial, in factored form is:  [ x - (1 - sqrt(3)) ] · [ x - (1 + sqrt(3)) ] · [ x - (2 + sqrt(3) ] · [ x - (2 - sqrt(3) ]  =  0

Expand this expression for your answer.

Guest is right, 30, 60, 90 is the answer.

180 - 90 = 90

The two other angles have to equal 90 degrees and form an arithmetic sequence. 30, 60, 90 is the only sequence that fits both conditions.

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There are four 2's, four 4's, four 6's, four 8's, four 10's, and four jacks, four queens, and four kings. There are 26 red.

26 red cads + 2 twos + 2 fours + 2 sixes + 2 eights + 2 tens + 2 queens + 2 kings + 2 jacks = 42

42/52 = 21/26

So, the answer is 21/26.

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Since you have two six-sided die, you have 2 sets of 1-6.

Set 1: 1,2,3,4,5,6

Set 2: 1,2,3,4,5,6

Now, we need to find out how many items in the sets add up to equal a sum less than 4.

1 + 1 = 2

2 + 1 = 3

We can roll a 1 and a 1 with a 1/6 chance each.

We can also roll a 1 and a 2 with a 1/6 chance as well.

So, to get the final probability, we would multiply the two fraction together.

1/6 x 1/6 = 1/36

There is a 1/36 chance that the sum of the numbers you roll will be less than 4.

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The center of the circumcircle of a right triangle is the midpoint of the hypotenuse.

This makes the radius of the circumcircle one-half the diameter = 58 / 2  =  29.

The area of the circumcircle is  pi · 29²  =  841 · pi

By a well-known theorem (a polite way to say "look it up"), the radius of the incircle of a right triangle is found

by adding the two sides together, subtracting the hypotenuse and then dividing this answer by 2.

The radius of the incircle is (40 + 42 - 58) / 2  =  12

The area of the incircle is  pi · 12²  =  144 · pi

Subtracting, the answer becomes  697·pi

The only way to get a sum less than 3 is to get a 1 on each of the two dice.

The probability of getting a 1 on the brown die is 1/6.

Similarly, the probability of getting a 1 on the black die is 1/6.

To find the final probability, multiply these two probabilities together:  1/6 x 1/6  =  1/36.

angle(DCB) = angle(CBA) = 40^o 

angle(CAB) = angle(CBA) = 40^o

This makes angle(ACB) = 80^o

8.6 rounded 9 minutes

Let's set Joe has 3x stamps initially. So

3x + 5x * 4/5 * 3/8 + 96 = 8x + 5x * 4/5 * 5/8

3x + 3/2x + 96 = 8x + 5/2x

6x + 96

x = 16

So 3 * 16 + 3/2 * 16 = 72

The number of stamps Joe: Alex: Sam = 3:8:5

Let the ratio be 3x : 8x : 3x

Sam keep 1/3 of his stamps the rest of the stamps given to

Joe and Alex the rest if 4/5 of 3x that is 4x

in ratio 3:5 that is 1.5x : 2.5x

Alex had 96 stamps more than Joe

Alex: 2.5x + 8x

Joe: 1.5x + 3x

2.5x + 8x - 3x - 1.5x = 96

6x = 96

x = 16

Joe: 1.5 * 16 + 3 * 16 = 72 stamps

So Joe had 72 stamps in the end

Well, this took a buttload of work but I finally managed to figure it out. The answer is 697 pi :)

 Find the measure of arc LPM.

Hello Guest!

Over an arc of a circle, the peripheral angle = 1/2 central angle.

\({\color{blue} ∠\ LPM}=\frac{1}{2}\cdot ∠\ LOM\\ {\color{blue}∠\ LPM=36^o}=\frac{1}{2}\cdot 72^o\)

The arc of the large circle from L via P to M is equal to 360 ° - 72 °, i.e. 288 °.

What is the meaning of the smaller circle, please?

  !

sumfor(k, 1, 100,  (-1)^(k - 1)*k/(3^k))==it converges to 3/16==0.1875

The area of the square is 108.

The answer is 2.

There will be six intersection points, one for each square.

The sequence is 30, 60, 90 

If  x ,  y , and  z  are positive...

\(\frac{x}{|x|}+\frac{y}{|y|}+\frac{z}{|z|}+\frac{xyz}{|xyz|}\,=\,\frac{x}{x}+\frac{y}{y}+\frac{z}{z}+\frac{xyz}{xyz}\,=\,1+1+1+1\,=\,4\)

If only  x  is negative...

\(\frac{x}{|x|}+\frac{y}{|y|}+\frac{z}{|z|}+\frac{xyz}{|xyz|}\,=\,\frac{-|x|}{|x|}+\frac{y}{y}+\frac{z}{z}+\frac{-|x|yz}{|xyz|}\,=\,-1+1+1-1\,=\,0\)

If only  y  or only  z  is negative, the result will also be  0 .

If  x  and  y  are negative, and  z  is positive...

\(\frac{x}{|x|}+\frac{y}{|y|}+\frac{z}{|z|}+\frac{xyz}{|xyz|}\,=\,\frac{-|x|}{|x|}+\frac{-|y|}{|y|}+\frac{z}{z}+\frac{(-|x|)(-|y|)z}{|xyz|}\,=\,-1-1+1+1\,=\,0\)

If any two are negative, the result will also be  0  .

If  x ,  y , and  z  are negative...

\(\frac{x}{|x|}+\frac{y}{|y|}+\frac{z}{|z|}+\frac{xyz}{|xyz|}\,=\,\frac{-|x|}{|x|}+\frac{-|y|}{|y|}+\frac{-|z|}{|z|}+\frac{(-|x|)(-|y|)(-|z|)}{|xyz|}\,=\,-1-1-1-1\,=\,-4\)

So, the answer is -4, 0, and 4!!

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distance = rate * time, so d = rt
therefore r = d/t 
r = 0.5mi/0.75hr = 0.67 mi/hr

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How many different triples (a,b,c) from the set {1,2,3,4,5} satisfy the equation a^2 + bc = b^2 + bc

a^2 + bc = b^2 + bc

a^2  = b^2 

since there are no negative choices, a=b   c can be any number

If numbers cannot be reused then there are no solutions

if numbers can be reused then there are 5*5=25 triplets

\(SA=4\pi r^2\\ \pi\approx 3\quad r=2\\ SA\approx 4*3* 2^2\\\)

You can finish it.