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GuestSep 4, 2013

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GuestSep 4, 2013

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(cubic root of 8) ^2 =====> 2^2=4

GuestSep 4, 2013

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5^3*y^2
and if u need to expand it more ( I don't think so): 125y^2

GuestSep 4, 2013

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You haven't stated what units you would like the density to be shown in (usually it is kg/litre)

So density = mass/volume

density = 0.04kg/64cm^3 (64cm^3 came from 4cm x 4cm x 4cm) or if you want this in litres: 1000cm^3 = 1 litre, therefore: 1000/64 = 15.625 then multiply by 0.04 = 0.625kg/l

GuestSep 4, 2013

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If you take the reciprocal of a fraction (reciprocal x = 1/x) it is the same as taking the fraction and 'turning it upside down'. So in this case 3x/2 is the simplest form. The logic is that you multiply both the denominator (bottom) and numerator (top) of the fraction by 3x (in this case).

GuestSep 4, 2013

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10% of 11 dollars = 1.10 dollars (because 10% is one tenth). Therefore your total cost = 11 - 1.10 = 9.90 dollars

GuestSep 4, 2013

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Sorry - I should have added the 36 and not subtracted it!

GuestSep 4, 2013

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7^3 = 7 x 7 x 7 = 343
6^2 = 6 x 6 = 36

So if I read your question correctly

343 - 36 - 2 = 305

GuestSep 4, 2013

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-2

Why? -2 x -2 = +4, +4 x -2 = -8

GuestSep 4, 2013

+104

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So the square root of 2 would also be a rational number, because 2 is rational? Of course not.
6 is a rational number, thats correct.
But as we know, every square root of a number n is either an irrational number or an integer.

Claim: sqrt(6) is a rational number.
Therefore we could create an equation like sqrt(6) = n/k with n,k being integers > 1.
6 = (n/k)^2 = (n^2)/(k^2)
6*k^2 = n^2

We can see, that 6*k^2 is always even n^2 is also even n is even
So we rephrase the equation with 6*k^2 = n^2 = (2a)^2; n = 2a
(6*k^2)/2 = 2a^2 = 3*k^2

2a^2 is always even. Therefore 3*k^2 has to be even. This is only the case if k is even.
k = 2b
2a^2 = 3*k^2 = 3*(2b)^2 = 3*4b^2 = 12b^2
a^2 = 6b^2
etc.

sqrt(6) won't result in an integer. So there shouldn't be two even integers.

ApfelkuchenSep 4, 2013

+104

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2^(999,999,999,999,999) is a logical left shift of 1 by 999,999,999,999,999.
Most common is an implementation of 32-bit blocks. So you'll need at least 999,999,999,999,999/32 ~ 31250000000000 blocks.

ApfelkuchenSep 4, 2013

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subtract 9 from 21 which would equal 12 then divide by 15n.. 15n=12 or 12/15

GuestSep 4, 2013

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1/2= 0.5 1/4= 0.25, and so on....

GuestSep 4, 2013

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Use BIDMAS

Bracets
Indices
Division
Multiply
Add
Subtract

GuestSep 4, 2013

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You need to times the uniform cost by the amount of uniforms purchased

GuestSep 4, 2013

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GuestSep 4, 2013

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Try finding the constraints in the given problem
perimeter of rink is 570 ft ( i )
let x be the width of the field
so x+115 will be the length.
once you get this, rest is simple.

Now from Perimeter of the rink will be (as the rink is rectangular)
= 2x + 2(x+115)
= 4x + 230 ( ii )

from ( i ) and ( ii )
4x + 230 = 570
4x = 340
x = 85

width = x = 85, length = x+115 = 200
Now you know both the dimensions

GuestSep 4, 2013

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1 + 1/4 = 1 + .25 = 1.25

GuestSep 4, 2013

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GuestSep 4, 2013

Sep 3, 2013

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Apfelkuchen:
sqrt(6) = sqrt(2*3) = sqrt(2) * sqrt(3)
2 and 3 are prime numbers. You've got two prime numbers without an even exponent. The square root of every prime number is an irrational number sqrt(6) is an irrational number.

actualy 6 is a whole number and whole numbers are always rational irrational numbers are not whole not a integer or natural
therefor it cant be irrational

GuestSep 3, 2013

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I CANT EVEN DO THAT
(JK)

GuestSep 3, 2013

+104

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sqrt(6) = sqrt(2*3) = sqrt(2) * sqrt(3)
2 and 3 are prime numbers. You've got two prime numbers without an even exponent. The square root of every prime number is an irrational number sqrt(6) is an irrational number.

ApfelkuchenSep 3, 2013

+104

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Per def. mean score: k = Σ(n_i, i = 1...k)/k

Σ(x_i, i = 1...6)/6 = (x_1 + x_2 + x_3 + x_4 + x_5 + x_6)/6 = 14.5 [*6]
x_1 + x_2 + x_3 + x_4 + x_5 + x_6 = 14.5*6 = 87

7. game:
Σ(x_i, i = 1...7)/7 = (x_1 + x_2 + x_3 + x_4 + x_5 + x_6 + x_7)/7 = 16 [*7]
x_1 + x_2 + x_3 + x_4 + x_5 + x_6 + x_7 = 16*7 = 112
x_7 = 112 - (x_1 + x_2 + x_3 + x_4 + x_5 + x_6) = 112 - 87 = 25

ApfelkuchenSep 3, 2013

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scrutinizer:
4/3+3m/5=41/15. Note that the both items of the left side can be reduced to the common denominator 15. (20 + 9m)/15 = 41/15. Breaking free of the denominator by multiplying both sides by 15 we get 20 + 9m = 41 => 9m = 21 =>m = 21/9 = 7/3

[input]solve(4/3+3*m/5=41/15, m)[/input]

GuestSep 3, 2013

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