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0

wow i didn't know that that was helpful

GuestSep 6, 2013

0

The first thing to do is get all your masses in the same units. You can either convert the mass into kilograms, or your density into grams/metres^3. I'll do the second one.

The conversion rate for kilograms to grams is 10^3g/1kg. This fraction is actually the number 1, because both the top and the bottom are exactly the same. This means you can multiply the density of your object by the fraction, and get the exact same density in a form that will be a lot easier to work with. (Anything times 1 is still what you started with).

(1.98x10^3 kg/m^3) (10^3g/1kg) = (1.98x10^3kg x 10^3g)/(m^3 x kg) (multiply top and bottom of your fractions)
= (1.98x10^6 kg g)/(m^3 kg) (combine powers of ten)
= 1.98x10^6 g/m^3 (cancel kg on top and bottom)

The formula for density is Density = Mass/Volume. Solving for Volume gives Volume = Mass/Density. Inserting your numbers into the equation:

V = (35.4 g)/(1.98x10^6 g/m^3)
V = 35.4/(1.98x10^6 / m^3) (cancel g on top and bottom)
V = 35.4 m^3/1.98x10^6 (multiply top and bottom of fraction by m^3)
V = 1.79x10^-5 m^3 (resolve the fraction)

Remember, you want your answer in cm^3, not m^3. So we need another conversion rate. Knowing that 100 cm/1 m = 1, and that 1^3 = 1, we can say that:

(100 cm/1 m)^3 = 1
100^3 cm^3/m^3 = 1 (cube everything in the brackets)
10^6 cm^3/m^3 = 1

And multiplying your answer by "1" gives you:

(1.79x10^-5 m^3 x 10^6 cm^3)/(m^3) (multiply top and bottom of your fractions)
1.79x10^-5x10^6 cm^3 (cancel m^3 on top and bottom)
17.9 cm^3 (combine powers of ten; simplify)

So your final answer is 17.9 cm^3. Hope this helps!

GuestSep 6, 2013

0

O KAY uh like:
say...
1=9-6*1-2
2=
3=
4=
5=
6=
7=
8=
9=
10=
etc....
so like all those blank numbers, i am suppose to, like
EXAMPLE:9-6*1-2=1 so i will put that work on 1 like this see?

GuestSep 6, 2013

0

Uh to just let you know that you could do um... i dont get your problem can you show me more? please.

GuestSep 6, 2013

0

To divide a variable by a number, you simply form a fraction. Simply, x divided by 7 is x/7. This works both ways; 7 divided by x is 7/x.

So for the equation 3x = 6y + 5 (solve for y)

3x - 5 = 6y (subtract 5 from both sides)
3x/6 - 5/6 = y (divide both sides by 6)
x/2 - 5/6 = y (simplify the left hand side)

Just remember, variables behave the same as any other number in a fraction. Happy solving!

GuestSep 6, 2013

0

use the 1/x button

GuestSep 6, 2013

+1

5/8 cups was spilled

GuestSep 6, 2013

Sep 5, 2013

0

GuestSep 5, 2013

0

4825.92 metres is 15,833.071 feet

GuestSep 5, 2013

+259

0

A/q - 1 = wk => w = (A/q - 1)/k

scrutinizerSep 5, 2013

+259

0

x^4-20x^2+64 = 0, y = x^2 => y^2 - 20y + 64 = 0 => y1 = 16, y2 = 4 --> x^2 = 16 --> x = +-4. x^2 = 4 --> x = +-2

solve(x^4-20x^2+64 = 0, x)

scrutinizerSep 5, 2013

+259

0

[input]solve(x^7=2,x)[/input]

[input]sqrt(2,7)[/input]

scrutinizerSep 5, 2013

+259

0

Depends on the measurement of the angle. For those that are multiples of the angles of 0,30,45,60,90 degrees there are commonly accepted values that are to be memorized much like times table is. For other angles, if you need an exact value, you can look into table of values for the trigonometric functions. However, there a sort of tasks exists where a value is required to be found on your own without the use of tables and calculators. Tan of what an angle exactly do you need to find?

scrutinizerSep 5, 2013

+259

0

Rather, it would transpher the graph 3 points up Y-direction

scrutinizerSep 5, 2013

0

Actually -1 = a-(1+a) = a-1-a =(a-a)-1 = -1

GuestSep 5, 2013

0

what if its a fraction i dont know what the decimal is.

GuestSep 5, 2013

0

-1=a-(1+a)
-1-a=1+a
-1=1+2a
-2=2a
-1=a

GuestSep 5, 2013

0

3 - (1/5)x = -7

Easily done if you make your variable a whole number.

(1/5) * 5 = 1

So multiply your whole equation by 5.

5 * (3 - (1/5)x = -7)

15 - x = -35

Get the variable by itself by subtracting 15 from both sides leaving:

-x = -50

Multiply the equation by (-1) or simply take away the negatives on both sides. (Same difference in this situation)

x = 50

GuestSep 5, 2013

0

(3 and 7/10) / (2 and 2/9)

Translates to:

(37/10) / (20/9)

Flip the divisor and convert to multiplication:

(37/10) * (9/20) = 333/200

GuestSep 5, 2013

0

You begin by getting the absolute value equation on its own. You do that by adding 1 to both sides, then dividing by -8.

|-2x+1|= 5

Then you solve the absolute value equation by writing two equations. One equation is set to equal 5, while the other equation is set to equal -5.

-2x+1= 5

and

-2x+1= -5

Solve each like normal equations and you get x=-2 and x=3

GuestSep 5, 2013

0

A-q all over qk= w

A-q
_____ = w

qk

GuestSep 5, 2013

0

Depends where the angle is located. Not enough info is given.

GuestSep 5, 2013

0

In the first equation, you only add the exponents. In the second equation, you multiply the exponents.

GuestSep 5, 2013

0

A = q + qwk
A = q(1 + wk)
A/q = 1 + wk
A/q - 1 = wk
(1/w)(A/q - 1) = k

GuestSep 5, 2013

Sep 4, 2013

0

if you add what number you get 7 .. but positives and negatives

GuestSep 4, 2013

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