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No set of integers has a sum which is 15/4s more than any of its integers.

1/3 = 50000

3/3 = 150000

1/4=150000

4/4=600000

1/5=600000

5/5=3000000

To find the x-intercept, replace y with 0 and solve.

To find the y-intercept, replace x with 0 and solve.

The number of degrees in the interior angles of a quadrilateral is  360^o.

Solve this equation for q:       (q) + (5q + 15) + (3q - 55) + (4q - 20)  =  360

and, using that value for q, find:

                             q  =

                   5q + 15  =

                    3q - 55  =

                    4q - 20  =

step by step explanation:

the angles on the inside of the pentagon=

\(180\times(5-2)=540\)

the angles on the inside of the trapezoid =

\(180\times(4-2)=360\)

7x360-360-540=

5x360-180=

1800-180=1620.

But we counted F and C as 360 + F and 360+c, so

1620-720=\(\boxed{900}\)

I agree

3 (a) Let w = a + bi and z = c + di.  The rest is expanding.

(b) Let w = a + bi and z = c + di.  Then

\(\dfrac{w + z}{1 + wz} = \dfrac{a + c + bi + di}{1 + (a + bi)(c + di)}.\)

To express this in rectangular form, we can multiply the numerator and denominator by the conjugate:

\(\dfrac{a + c + bi + di}{1 + (a + bi)(c + di)} = \dfrac{(a + c + bi + di)((1 - (a + bi)(c + di))}{(1 + (a + bi)(c + di))(1 - (a + bi)(c + di))}.\)

The denominator simplifies to (1 - (a^2 + b^2)(c^2 + d^2)), which is real.  The numerator simplifies to a^2 - b^2 + c^2 - d^2, which is also real.  Therefore, the complex number (z + w)/(zw + 1) is real.

We're trying to optimize the quadratic, to do this we must complete the square. 

The equation should turn out in the form of 

h = -a(x + b)^2  + c

Since -a(x + b)^2 must be non positive, it can at most be 0, when x = -b. 

So the height maximized is c. 

=^._.^=

Ax + By = C

-3A - 5B = C

8A + B = C

8A + B = -3A - 5B

11A + 6B = 0

Can you take it from here?

=^._.^=

8x + 1 = 5 + 3x (mod 12)

5x = 4 (mod 12)

5(5x) = 4(5) mod (12)

x = 8 mod (12)

=^._.^=

NUMBER OF PLAYERS

JEFFRY ELIMINATED = 100

NUMBER OF PLAYERS

  RYAN ELIMINATED = 1/2 * 100

                                   = 50

BOTH ELIMINATE = 100 + 50

                               = \(\boxed{150\ PLAYERS}\)

First three shapes:   k = 1/3,       k = 1/5,        k = 1/4

I answered this or something very similar a few days ago.  Go see if you can find it.

Added:

I just googled you exact question and found an anwer immediately.

b + c + 6 = 15

b = 9 - c

c² = 6² + (9 - c)²

c = 6.5

The sum of the angles is 1620 degrees

Which digits are in "the set"?

If the set consists of all ten digits, then there are 1000 possible combinations.

Of these 30 are not allowed:  02x, 0x3, x23 (where x is any of the ten digits.

In this case there are 1000 - 30 allowable combinations.

Your numbers are wrong!!! 

EG must be smaller than AD!!!

The area of the parallelogram is the base times the height.

If you consider the base to be CD and the height to be GE, the area = 27 x 40 = 1080.

However, you could consider the base to be AD and the height to be FH (it will have the same area).

     1080  =  18 x FH     --->     FH  =  60

quotient      =  t2 + 3t + 2

remainder  =  -9t - 19

x = 1 - sqrt(2)] and x = 2 + sqrt(7).

\(f(x)=(x-(1-\sqrt2))(x-(1+\sqrt2))(x-(2-\sqrt7))(x-(2+\sqrt7))\)

That should do it.  You can expand.  Try graphing it using desmos to check it is right first ;)

What a load of rubbish.
If they were given to you as a fun challenge and you are trying to get them done here then you are cheating on your freinds challenge.

More likely you are cheating on school work.

Either way, your aim with this post is to CHEAT!

Your cheat questions are blocked, not that that anyone would be likely to bother with them anyway.

pls I need answers too