81 - 9 = 72 72 is the answer
This is impossible
Look at triangle BDI
BD = 3 DI = 3 and BI = 6
By the triangle inequality theorem, BD + DI must be greater than BI
But
BD + DI = BI
So......this inner triangle cannot exist
We have that
AQ * BQ = CQ * DQ
Let CQ = x and DQ = 38 - x
So
6 * 14 = x * (38 - x)
84 = 38x - x^2 reararrange as
x^2 - 38x + 84 = 0
Using the Quadratic Formula the minimum for x = CQ ≈ 2.3567
Volume of a square pyramid = (1/3) base^2 * height =
(1/3) ( 5)^2 * 15 =
(1/3) ( 25) * 15 =
125 in^3
81 - - sqrt81 = 81 + 9 = 90
6/8 are still at school
6/8 ( 30 + 26) = ___________
(1/7)10 is the same in base 8 (1/7)8 However the decimal representations are different (1/7)8 = .1111118
6 x sqrt (90) = 56.92 so answer would be 57
Tried that, it doesn't work.
yes i have a sulution for you! Just hit the right arrow key on your keyboard until the cursour moves after the LaTex
also this is what an non-adblocker version looks like
https://web2.0calc.com/questions/why-cant-i-use-the-calculator#r8
This is the link to my previous problem. It was resolved and i asked admin about it. Hes the one who owns web2.0 calc right?
Hey There! I might be able to assist you. Can you tell me what youve tried and upload screenshots? Ive been able to resolve this before
-Elijah
Cosine rule in PQR:
\(\displaystyle \cos Q = \frac{13^{2}+14^{2}-16^{2}}{2.13.14}\; . \)
Cosine rule in PQM:
\(\displaystyle PM^{2}=7^{2}+13^{2}-2.7.13.\cos Q .\)
All values of n from 5, 11, 17, 23, 29, 35, 41, 47............497, which is:[6n - 1]
[497 - 5] / 6 + 1==83 such values of n.
n+q=63
5n+25q=1075
solve simultaneously
I think the no accounts is just a temporary problem.
Thx so much bro!
Let x = John's stamps
2/7 is equal to Lawrence's stamps 1/5x = 2/7 (350)
1/5x = 100
x = 500 stamps
you're the one that's toxic
......Since the site seems to be slowly dying.....no one can sign up for accounts any longer....I am quite suprised ANY advertisers would be interested.
10 * 10 * 0 + 0 + 0 + 1 + (89/8) + 3 + 3i + 4i + 9i + 10 + 10/0+6 * sqrt of i^2 + -3
See the red part....it makes the whole thing 'undefined' . You cannot divide by zero.
im sorry, Given that (3,4) is a point on the graph of y=f(x), what point must be on the graph of
y= -4f(-2x) + 3