the limit diverges
to see why, as n approaches infinity, the terms approach 5/4, which is nonzero and therefore diverges.
t^2-8t-10=0
t^2-8t=10
t^2-8t+16=10+16
(t-4)^2=26
t-4=+(26^(1/2))
t=4+(26^(1/2))
t=9.1s
i think it is -27.16
No. You were very close though, but the answer is x+y-7>0
But thank you for helping me! :)
The inequality is x + y + 1 > 0.
the pentagon has equal angles so the inside angle is 108 to get 360 the circle angle inside 108+108=216 360-216=144
(Give your answer in "standard form" or where and are integers with no common factor greater than 1.)
145 cm = 1450mm
9 cm = 90 mm
Volume of 10 pencils = 10 pi (4.5)^2 * 145 ≈ 92,245 mm^3
Volume of box = 1450^2 * 90 = 189225000 mm^3
floor [ 189225000 / 92,245 ] = 2051 packages
The greatest distance = the body diagonal of the cube
8 = sqrt ( s^2 + s^2 + s^2)
8 = sqrt (3 s^2)
8 = s sqrt (3)
s = 8 /sqrt (3)
Volume = side^3 = (8/sqrt (3))^3 = [(512) / 3] / sqrt 3 = ( 512sqrt(3) / 9 ) in^3
look at this https://web2.0calc.com/questions/roots_26
almost same problem here https://web2.0calc.com/questions/let-f-x-be-a-polynomial-such-that-f-0-4-f-1-5-and_1
x^4 + 4x^2 > -4
x^4 + 4x^2 + 4 > 0
(x^2 + 2)^2 > 0
all x values make this true
x^4 + 4x^2 < 21 + 8x^2
x^4 - 4x^2 - 21 < 0
(x^2 -7) ( x^2 + 3) < 0
The interval ( -sqrt 7 . sqrt 7 ) makes this true...and this is the solution
r = sqrt [ (- 3 )^2 + 5^2 ] = sqrt [ 34]
sin = y/ r = 5/sqrt (34) = (5/34)sqrt (34)
csc = r/ y = sqrt (34) / 5
cos =x / r = -3/sqrt (34) = (-3/34) sqrt (34)
sec = r / x = -sqrt (34) / 3
tan = y/ x = 5/-3 = -5/3
cot = x /y = -3/5
3.8 * 4.2 = 15.96 miles ≈ 16 miles
6! is 720 3! is 6
720/6 is 120 so its 120
P
120
A 30 30 B
75 75
30
Q
PAQ = PAB + BAQ = 30° + 75° = 105°
1/3 < M/30 < 5/3
1/3 < M /30 and M/30 < 5/3
30 (1/3) < M M < (30) (5/3)
M > 10 M < 50
Number of integers = (49 - 11) + 1 = 39
21/7 is 3 so kate is 3 years old 10*7 is 70 so gracie is 70 in dog years so 70-3 is 67
i think???
(1/2) ((2/3 * 3/4) * (2/3 * 3/4) )
(2/3 * 3/4) = ( 2/3 - 3/4) / ( (2/3)^2 + (3/4)^2 ) = (-1/12) / ( 4/9 - 9/16) = ( -1/12) / ( -17/144) =
12/17
So
(1/2) * ( 12/17 * 12/17) = (1/2) * ( [ 12/17 - 12/17 ] / [ (12/17)^2 + (12/17)^2 ]) = (1/2) * 0 =
(1/2 - 0 ) / [ (1/2)^2 + 0^2 ] = (1/2) / (1/4) = ( 4/1) * (1/2) = 4/2 = 2
this would make 2 triangles use this https://www.calculator.net/triangle-calculator.html?vc=&vx=11&vy=9&va=42&vz=&vb=&angleunits=d&x=46&y=15
7 intgers 11,12,13 ,14 ,15 ,16 ,17
its C 29.11
The denominator cannot = 0
So x^2 -7x +6 = (x -6) (x - 1) so x cannot be 1 , 6
Also x^2 - 7x + 6 must be ≥ 0
(x -1) (x -6) ≥ 0
This is true whenever x < 1 and x > 6
The domain is ( -inf , 1) U ( 6 ,inf)
