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The percent is 35%.

x = 4 + 3i and 4 - 3i.

t = 7 + sqrt(5) and t = 7 - sqrt(5)

The solutions x are 12 and -9.

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That's after everyone posted it...

NMigosjfjd

105?

I don't know what's the answer

The solutions are 4 and -3.

x + x + 32 + y + 5/6y = $844

2x + 11/6y = $844 - $32

2x + 11/6y = 812 

x + 36 = 1 1/2 (5/6y)

x + 36 = 3/2 * 5/6y => x + 36 = 5/4y

4/5 (x + 36) = y

2x + 11/6 (4/5 (x + 36)) = 812

2x + 22/15x + 52.8 = 812 => x = 219

$219 at first 

The vertex would be at (-2,-2).

log_b(5^2) = 2log_b(5) = 28

Note that we use stars and bars for this method to prevent overcounting. 

We have 4 stars and 3 bars to sort the 4 remaining flowers, and the number of orderings is how many ways we can order the stars and bars, making for \({7 \choose 3} = \color{brown}\boxed{35}\) options. 

Rearrange as

x^2 - 2x - 3 =  0         factor

(x  - 3 ) ( x + 1)   = 0       

x - 3  =  0                 x + 1  = 0

x = 3                       x = - 1

(3)^2  + (-1)^2 =  

9 + 1   =

10

See EP's answer here :   https://web2.0calc.com/questions/please-help-and-if-possible-could-you-explain-step-by-step

Let the center =   O

Draw OB

Then OA =  OB    so in triangle OAB  angles   BAO   and ABO   are equal    =  60°

So angle OAB  also =  60°

And  arc   AB   =   60° =   1/6 of the circle's circumference

The radius of the circle =  18

So   arc   AB =   (1/6)* 2 * pi ( 18)  =    6 pi 

Answered under your original post

Suppose we have 12 members of a set

We have 8 orchids in  the set by default

Of the other 4  flowers in  the set (making a  dozen in total)  we have 4 ways to choose a flower in  each of the remaining 4 positions

So.....total number of possible boquets (sets)  = 4 * 4 * 4 * 4  =    256

144 measures  x  12 notes per measure ==1728 notes.

1728 / 560 ==3 + 48/560 minutes to play the entire Prelude

[3 + 48/560] minutes x  60 seconds per minute ==185 + 1/7 - seconds to play the entire prelude.

f (2x)  means  that  the original function is  horizontally compressed by a factor of  2

So....the original  domain  has a width of 10......the new domain has a width of 5

As written we have

8 / 2 * ( 2 +2)  =

4  *  4  =  

16

This  = 1  is if we have

8/ [ 2 ( 2 + 2) ] = 

8 / [ 2 * 4 ] =

8 / 8   =  1

{Thus emphsizing the importance  of brackets and parentheses  !!!   }