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7695575, but next time type that into the calculator in the home page of this website instead of spamming the forum.

The answer is -22222222222574, but please don't continue to spam this forum.

10 to the power of anything is just one followed by zeroes(unless the exponent is negative). The number of zeroes is the value fo the exponent. So 10^3 is 1000. Then, you multiply it by 2, in which all you have to do is multiply the 1 in the 1000 by two, and you will get 2000.

So, yes, 2000=2x10^3.

The function could be many things, including in1+in2x0, which would be the simplest answer, but you did not give enough information to narrow it down to only one answer.

There are two meanings of analytic geometry. One is the study of geometry using the coordinate system. The other is basically algebraic geometry.

I think we have.....

.08 = [(.75x)/(1- .75x)]   subtract the expression from the right hand side to set the expression = 0  .....and using the on-site solver, we have......

$${\mathtt{0.08}}{\mathtt{\,-\,}}\left({\frac{{\mathtt{0.75}}{\mathtt{\,\times\,}}{\mathtt{x}}}{\left({\mathtt{1}}{\mathtt{\,-\,}}{\mathtt{0.75}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}}\right) = {\mathtt{0}} \Rightarrow {\mathtt{x}} = {\frac{{\mathtt{8}}}{{\mathtt{81}}}} \Rightarrow {\mathtt{x}} = {\mathtt{0.098\: \!765\: \!432\: \!098\: \!765\: \!4}}$$

So its 0.08=0.75x divided by 1 then take away 0.75?

But how does that work? could you do a step-by-step?

Yes i copied it correctly i also keep getting 0 but the answer sheet for the finance class it is for says x equals 0.0988 so i want to know how they got that answer...

10^{log₁₀ (10^10)}

Whenever we have something like this...... a^log_ab   the answer is just "b"

So we have

10^{log₁₀(10^10)}

And the answer is just .....  10^10

Check this question. http://web2.0calc.com/questions/logarithm_5

Yes. 10^3 = 1000 * 2 = 2000

Im assuming you want to simplify.

6(5w-2x)-(4w-x)

Multiply first bracket by 6.

30w-12x-4w+x

26w-11x.

Note.-(4w-x) is turned into -4w+x when brackets are removed because it is the same as +(-1(4w-x)), so multiplying the -x by -1 turns it into +x or just x.

Find out how many times you need to divide by 10 to get the remaining digit to between 1 and <10.

Then put you answer in here:

(final digit)*10^(number of times needed to divide by 10 to get a digit on its own 1<= and <10)

8*10^11.

Dividing by one on the second term is pointless: .75x/1 should be .75x

.08=.75x-.75x well... .75x-.75x is 0. Did you copy this right?

8.00000000000*10^11

First, expand brackets, so

-7x-7-6=-41x+55

Next, combine like terms. To do this, add 41x to both sides of the equals sign, so you get 34x-7-6=55.

Then move the -7-6/ -13 over by adding 13 to both sides.

34x=55+13

34x=68

Divide both sides by 34 to get x on its own.

x=2

There you have it, the answer is 2

-85.

Which two consecutive numbers total -171?  To quickly determine, divide -171 by two.  You get -85.5, a decimal.  The two integers on each "side" of that decimal are the two consecutive integers that total -171.  In this case, -85 and -86.  Since -85 is closer to zero, that's your answer.

Assuming that "?" retains the same value, let it = 'x"

So

x*x*x = 25

x³ = 25     take the cube root of both sides

x = ³√25

5^-2 = 1/5² = 1/25

10log10(10^10)

If we have

10log[10(10^10)]   ......then we have

10log(10)¹¹ =

log[(10)¹¹]¹⁰ =

log(10)¹¹⁰ =

110

If we have

10log₁₀(10^10)   .....then we have

10*log₁₀(10¹⁰) =

log₁₀(10¹⁰)¹⁰ =

log₁₀10¹⁰⁰ =

100

No, it is 100. use the calculator.

14.9*sin(22)/sin(113)   = about 6.064

6^2-3^2+1^-1   Ok...so we have

6^2 = 36

-3^2 = -9

+1^-1  = 1

And putting these all together, we have

36 - 9 + 1 =

27 + 1 =

28

I  just wanted to see if I could get Alan's answer using a different (albeit, more complicated) approach......

So we have

C(n,3)(3x)^3 + C(n,2)(3x)^2

C(n,3)(27x^3) + C(n,2)(9x^2)

27C(n,3)x^3 + 9C(n,2)x^2      and we're told that

27C(n,3) = (10)[(9)C(n,2)]       divide by 9 on both sides

3C(n,3) = 10C(n,2)

3[n!/((n-3)!3!)] = 10[n!/((n-2)!2!)]    divide by n! on both sides

3/[(n-3)!3!)] = 10/[(n-2)!2!]   simplify

(1/2)/(n-3)! = 5/(n-2)!       multiply by 2 on each side

1/(n-3)! = 10/(n-2)!          multiply both sides by (n-2)!

(n-2)!/(n-3)! = 10             the left side simplifies to (n-2)

n-2 = 10

So....n = 12......just as Alan found  !!!