listfor(n, 1,25, floor(2#(n)):
(1, 1, 1, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5)==75
What have you done towards answering,
Please discuss then someone, probably me, will help you more.
Taking the derivatives with respect to x, y, we get
2x + y + 3 = 0
x + 2y + 3 = 0
Solving, we get x = y = -1. Therefore, the minimum is (-1)^2 + 1 + (-1)^2 + (-1) + (-1) + 1 = 2
"There are three times as many th graders as there are students with blue eyes"
Your question is missing information...
Only 3 does.
The number of sides is 73.
The sum is 153.
The answer is x^2 - 6x - 55.
The answer is 183.
There are 55 numbers in the list.
Note that the floor part of x will always be an integer, so x must end in .8.
Now, let \(x = a + 0.8\), where \(a = \lfloor x \rfloor\)
We now have the equation \(2a + 0.8 = 4.8\), meaning \(a = 2\), so \(x = 2 + 0.8 = \color{brown}\boxed{2.8}\)
EP's back!
hi, I came here when you were still inactive, but you are legendary, right?
https://web2.0calc.com/questions/circles_101
https://web2.0calc.com/questions/simplify-1-3-5-199-2-4-6-200-202
There are \({7 \choose 2} = 21 \) choices
The only cases that work are (1, 4), (1, 5), (1, 6), (1, 7), (2, 5), (2, 6), (2, 7), (3, 6), (3, 7), (4, 7)
So, the probability is \({9 \over 21} = \color{brown}\boxed{3 \over 7}\)
By the quadratic formula, the solutions are 7/6 and 7.
